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Reptile [31]
3 years ago
8

Can someone pls find the area of this shape for me

Mathematics
2 answers:
OlgaM077 [116]3 years ago
8 0
Area of triangle = 1/2 x base x height

1/2 x 6 x 12
1/2 x 72
= 36cm2
bonufazy [111]3 years ago
4 0

Answer:

the area is 32

Step-by-step explanation:

add 12+13+6+1=32

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Solve for v 2(3v+8)=70
yuradex [85]

Answer:v = 9

Step-by-step explanation:

Simplifying

2(3v + 8) = 70

Reorder the terms:

2(8 + 3v) = 70

(8 * 2 + 3v * 2) = 70

(16 + 6v) = 70

Solving

16 + 6v = 70

Solving for variable 'v'.

Move all terms containing v to the left, all other terms to the right.

Add '-16' to each side of the equation.

16 + -16 + 6v = 70 + -16

Combine like terms: 16 + -16 = 0

0 + 6v = 70 + -16

6v = 70 + -16

Combine like terms: 70 + -16 = 54

6v = 54

Divide each side by '6'.

v = 9

5 0
3 years ago
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The area of a circle is 81pi square inches. what is the radius
FinnZ [79.3K]

Answer:

. r=9 inches is the answer.

7 0
3 years ago
Area of a circle with a diameter of 8 inches
gregori [183]

Answer:

8 divided by two equals the radius 4

3.14*4^2=50.24

Hope This Helps!!!

7 0
3 years ago
F(x) = 3x + x3
____ [38]

Answer:

Please check the explanation.

Step-by-step explanation:

Given

f(x) = 3x + x³

Taking differentiate

\frac{d}{dx}\left(3x+x^3\right)

\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'

=\frac{d}{dx}\left(3x\right)+\frac{d}{dx}\left(x^3\right)

solving

\frac{d}{dx}\left(3x\right)

\mathrm{Take\:the\:constant\:out}:\quad \left(a\cdot f\right)'=a\cdot f\:'

=3\frac{d}{dx}\left(x\right)

\mathrm{Apply\:the\:common\:derivative}:\quad \frac{d}{dx}\left(x\right)=1

=3\cdot \:1

=3

now solving

\frac{d}{dx}\left(x^3\right)

\mathrm{Apply\:the\:Power\:Rule}:\quad \frac{d}{dx}\left(x^a\right)=a\cdot x^{a-1}

=3x^{3-1}

=3x^2

Thus, the expression becomes

\frac{d}{dx}\left(3x+x^3\right)=\frac{d}{dx}\left(3x\right)+\frac{d}{dx}\left(x^3\right)

                    =3+3x^2

Thus,

f'(x) = 3 + 3x²

Given that f'(x) = 15

substituting the value  f'(x) = 15 in f'(x) = 3 + 3x²

f'(x) = 3 + 3x²

15 =  3 + 3x²

switch sides

3 + 3x² = 15

3x² = 15-3

3x² = 12

Divide both sides by 3

x² = 4

\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

x=\sqrt{4},\:x=-\sqrt{4}

x=2,\:x=-2

Thus, the value of x​ will be:

x=2,\:x=-2

5 0
3 years ago
Which is the function of the exoskeleton in animals?
Lina20 [59]
C) Protects against their environmental
8 0
3 years ago
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