The value of the median, lower and upper quartile
- Median = 21.5
- lower quartile = 12
- upper quartile = 29
<h3>What is the five-number summary for this data set?</h3>
The minimum value = 10
The maximum value = 38
The median is the value that is found in the center of the data when it is ordered from lowest to highest. In the event that there is no value that precisely corresponds to the center, the value will be determined by taking the average of the values that are located on each side of the middle.
10 11 12 15 19 24 27 29 33 38
Median = 21.5
The intermediate value of the data that is located to the left of the median is known as the lower quartile.
10 11 12 15 19
lower quartile = 12
The intermediate value of the data that is located to the right of the median is known as the upper quartile.
24 27 29 33 38
upper quartile = 29
In conclusion, the 5 number summary is 10, 12, 21.5, 29, 38 → A
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Answer:

Step-by-step explanation:
We are given that


y(0)=0
y'(0)=1
By comparing with

We get


q(x)=0
p(x),q(x) and g(x) are continuous for all real values of x except 3.
Interval on which p(x),q(x) and g(x) are continuous
and (3,
By unique existence theorem
Largest interval which contains 0=
Hence, the larges interval on which includes x=0 for which given initial value problem has unique solution=
Answer:
(b) (c) (a)
Step-by-step explanation:
Standard Normal distribution has a higher peak in the center, with more area in this región, hence it has less area in its tails.
Student's t-Distribution has a shape similar to the Standard Normal Distribution, with the difference that the shape depends on the degree of freedom. When the degree of freedom is smaller the distribution becomes flatter, so it has more area in its tails.
Student's t-Distributionwith 1515 degrees of freedom has mores area in the tails than the Student's t-Distribution with 2020 degrees of freedom and the latter has more area than Standard Normal Distribution
Answer:
9
Step-by-step explanation:
5,7,8,10,12,12
5+7+8+10+12+12=54
54/(how many numbers there are, which is 6)=9.
Your mean value is 9.
We have been given two functions
and
. We are asked to find
.
We will use composite function property
to solve our given problem.
Now we will combine like terms as:


Therefore, the value of
would be
.