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Brut [27]
3 years ago
9

Find the largest consecutive integers whose sum is less than 46

Mathematics
1 answer:
zmey [24]3 years ago
5 0

The largest consecutive integers whose sum is less than 46 are x= 21 and x+1=22

Step-by-step explanation:

Let the integers be:

x and x+1

The sum of these integers is less than 46

x+(x+1)

Solving and finding value of x:

x+(x+1)

So, the integers will be less than 22.5

The largest numbers are: 21 and 22

So, the largest consecutive integers whose sum is less than 46 are x= 21 and x+1=22

Keywords: Finding integers

Learn more about finding integers at:

  • brainly.com/question/5496711
  • brainly.com/question/10435816

#learnwithBrainly

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Bingel [31]
Well, to find u, we have to remove all that is attached to it so the equation can just be u=...
   To find u, you have to remove what is attached to it, and that is -12. Then you have to look at the relationship between the -12 and u. The relationship is multiplication, and the opposite of multiplication is division, so all you have to do is divide both sides by -12. So;
-12u/-12=-24/-12
   The -12 cancels the -12, leaving u and the - in 12 cancels the - in 24. Leaving 24/12. And that is 2. Written as;
u=2
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5 0
4 years ago
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How much times can 6 go into 48
DENIUS [597]
6 can go into 48 8 times. How I figured out?
Start multiplying from a small number like
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3 years ago
You own an accessories store, and sales last month were $24,000. You had $3,500 in discounts and $975 in returns.
Len [333]

Answer:

The net sales for last month were <u>$19,525</u>.

Step-by-step explanation:

Given:

Last month sales were $24,000.

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Now, to get the net sales for last month.

So, we deduct the discount:

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Then, we deduct the returns from the remaining amount:

<em>Sales after discounts - returns</em> = \$20,500 - \$975

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Help me to solve this one too please?
Flura [38]

Answer:

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Step-by-step explanation:

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