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Ivan
3 years ago
13

X = cos(2t) and y = sin(2t) Find the second derivative

Mathematics
1 answer:
Elodia [21]3 years ago
3 0
Dy/dx = (dy/dt) / (dx/dt)
dy/dt = 2cos(2t)
dx/dt = -2sin(2t)

dy/dx = 2cos(2t)/-2sin(2t) = -cot(2t)

d^y/dx^2 = d(-1/tan(2t))/dx = (tan(2t) * 0 - (-1)*2sec^2(2t))/tan^2(2t) = 2sec^2(2t)/tan^2(2t) = 2csc^2 (2t)
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Step-by-step explanation:

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Write a linear function f with f(0)=7 and f(3)=1.
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a = ( 0 , 7 ) & b = ( 3 , 1 )

First need to find the slope using the following equation :

slope =  \frac{y(b) - y(a)}{x(b) - x(a)}  \\

slope =  \frac{1 - 7}{3 - 0}  \\

slope =  \frac{ - 6}{3}  \\

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We have following equation to find the point-slope form of the linear functions using the slope and one of the through points .

y - y(0) = m \times ( \: x - x(0) \: )

x(0) = x - coordinate \:  \: of  \:  \: through \:  \: point \\

y(0) = y - coordinate \:  \: of \:  \: through \:  \: point \\

m = slope

I choose point (( a )) to put in the equation.

y - 7 =  - 2 \times (x - 0)

y - 7 =  - 2x  + 0

y - 7 =  - 2x

Add sides 7

y - 7 + 7 =  - 2x + 7

y =  - 2x + 7

This the slope-intercept form .

Done...

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