Answer:
P= Rs 60000
A= Rs 79860
T=1 & 1/2 year = 3/2 years
= 3/2 x 2 = 3 half years
R= ?
Applying the formula A= P (1+r/100)^T
79860 = 60000 (1+ r/100)^3
79860/60000 = (1+r/100)^3
1331/1000 = (1+r/100)^3
root(3)(1331/1000) = (1+r/100)
11/10 = 1+r/100
11/10 -1 = r/100
1/10 = r/100
r= 10 %
Step-by-step explanation:
Answer: calculator boi
Step-by-step explanation:
<span>In 3 years, you will have $8,103.38
Formula:
</span>
<span>A = P (1 + r/n)<span> ^(nt)</span></span>
Where:
A = the future value of the investment/loan, including interest
P = the principal investment amount (the initial deposit or loan amount)
r = the annual interest rate (decimal)
n = the number of times that interest is compounded per year
t = the number of years the money is invested or borrowed for
14. -6m²-2m+1
15. 14x-24
16.3b²
17.14p+7
do you need the steps?
That would be :
4x – 10 = x2 – 5x + 10 ( y = 4x - 10 is substitute for y)
PROOF: y + 5x = x²<span> + 10
</span> (4x - 10) + 5x = x² + 10
4x - 10 = x² -5x + 10
<span>
</span>0 = x2 – 9x + 20<span> (liked terms are grouped and simplified)
PROOF: </span> 4x - 10 = x² -5x + 10
4x = x² -5x + 10 + 10
0 = x² -5x -4x + 20
0 = x² - 9x + 20
Solving:
x² - 9x + 20 = 0
x² - 5x - 4x + 20 = 0
(x - 5) (x - 4) = 0
⇒ x = 4 (as question says) OR x = 5
