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3 years ago

Which equation represents a line that passes through the two points in the table?

Mathematics

2 answers:

lesya [120]3 years ago

8 0

Answer: It’s A. Just did it

Step-by-step explanation:

wariber [46]3 years ago

3 0

Answer:

Step-by-step explanation:

use the points to find the slope (y-y1/x-x1) 3-5/3-6 = 2/3

the answers are all in point slope form so the slope is 2/3 and the point represented is 3,3

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ANSWER QUICKLY PLEASE

Jet001 [13]

Answer:

answer below:)

Step-by-step explanation:

sin C= $\frac{opposite side}{hypotenuse side}$ = $\frac{7}{25}$

cos C= $\frac{adjacent side}{hypotenuse side}$ = $\frac{24}{25}$

tan C= $\frac{opposite side}{adjacent side}$ = $\frac{7}{24}$

8 0

3 years ago

I really need help!!!! i need answer to c:

Aleks [24]

Answer:

76.3

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of

Ivenika [448]

The equation for the height of the rocket at time t given

$h= -16t^2+192t$

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

$h= -16t^2+192t$

$560 = -16t^2+192t$

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

$560 = -16(t^2 - 12t)$

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

$560/-16 = -16(t^2-12t)/-16$

$-35 = t^2 -12t$

Now we will move -35 to the righ side by adding 35 to both sides.

$-35+35 = t^2-12t+35$

$0 = t^2 -12t+35$

$t^2-12t+35 = 0$

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

$t^2-12t+35 =0$

$(t-5)(t-7) =0$

So by using zero product property we will get

$t-5 =0$

$t-5+5 = 0+5$

$t=5$

Also $t-7 =0$

$t-7+7 = 0+7$

$t=7$

So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

$h= -16t^2+192t$

$0= -16t^2 + 192 t$

$0 = -16(t^2-12t)$

$-16(t^2-12t) = 0$

We will move -16 to the other side by dividing it to both sides.

$-16(t^2-12t)/-16 = 0/-16$

$t^2-12t = 0$

We will take out the common factor t from the left side. By taking out t we will get,

$t(t-12) = 0$

We will use zero product property now. By using that we will get,

$t = 0$

ans also $t-12 = 0$

$t-12+12 = 0+12$

$t = 12$

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

6 0

3 years ago

Suppose the circumference of a circle is 3 pi. What is the diameter?

Charra [1.4K]

This was asked already
c=pid or
c=2pir

use first one
c=3pi
3pi=c=pid
3pi=pid
divide by pi
3=d
diameter=3 units

7 0

3 years ago

Read 2 more answers

An architect is sketching a blueprint of a patio for a new fence. On the blueprint, C is the midpoint of segment AD. Point B is

Gre4nikov [31]

Answer:

The length of AD is 32 feet

Step-by-step explanation:

Proportional distances

When distances are proportions of others, we can express all of them as relative fractions until we reach some known distance and solve for the desired length

Let's call x the length of AD. Given C is the midpoint of AD, then

$\displaystyle AC=CD=\frac{x}{2}$

Given B is the midpoint of AC, then

$\displaystyle AB=BC=\frac{AC}{2}=\frac{x}{4}$

If we know BC=8 feet

$\displaystyle \frac{x}{4}=8\ feet$

$\displaystyle x=32\ feet$

The length of AD is 32 feet

4 0

3 years ago