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navik [9.2K]
3 years ago
8

Find the LCM of 12 and 18

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
5 0

Answer: 36

Step-by-step explanation: To find the least common multiple or <em>lcm</em> of 12 and 18, begin by listing the first few multiples of each number.

<em>Multiples of 12</em>

1 × 12 = 12

2 × 12 = 24

3 × 12 = 36

Notice that we skipped 0 × 12 in our list of multiples. That's because 0 × 6 is 0 and our least common multiple can not be 0.

When listing the multiples of 18, it's a good idea to keep an eye on the list of multiples for 12 so that we will notice when we find a least common multiple.

<em>Multiples of 18</em>

1 × 18 = 18 ← is not multiple of 12

2 × 18 = 36 ← is a multiple of 12

Notice that we can stop here because all other multiples that we find will be greater 36. So the least common multiple of 12 and 18 is 36.

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When jumping, a flea rapidly extends its legs, reaching a takeoff speed of 1.0 m/s over a distance of 0.50 mm . part a what is t
pshichka [43]

The flea's acceleration is 1,000 m/s².

<h3>Further explanation</h3>

The problem we overlook this time is about uniformly accelerated motion.

The list of variables to be considered is as follows.

\boxed{u \ or \ v_i = initial \ velocity}

\boxed{u \ or \ v_t \ or \ v_i = terminal \ or \ final \ velocity}

\boxed{a = acceleration \ (constant)}

\boxed{d = distance \ travelled}

Given that a take-off speed of 1.0 m/s over a distance of 0.50 mm.  

The initial speed was zero from rest.  It was asked about flea's acceleration when she extends her legs.

The formula we follow for this problem are as follows:

\boxed{ \ v^2 = u^2 + 2ad \ }

  • a = acceleration (in m/s²)
  • u = initial velocity = 0 m/s
  • v = take off speed = 1.0 m/s
  • d = distance travelled = 0.50 mm

Converted 0.50 mm to meters: \boxed{0.50 \ mm = 0.50 \times 10^{-3} \ m = 5.0 \times 10^{-4} \ m}

<u>Steps:</u>

We set the formula so that the acceleration becomes the subject.

\boxed{ \ v^2 = u^2 + 2ad \ }

\boxed{ \ v^2 - u^2 = 2ad \ }

\boxed{ \ 2ad = v^2 - u^2 \ }

\boxed{ \ a = \frac{v^2 - u^2}{2d} \ }

Substitute all data into equations.

\boxed{ \ a = \frac{(1.0)^2 - (0)^2}{2(5.0 \times 10^{-4})} \ }

\boxed{ \ a = \frac{1}{10 \times 10^{-4}} \ }

\boxed{ \ a = \frac{1}{1 \times 10^{-3}} \ }

\boxed{ \ a = 1 \times 10^{3}\ = 1,000 \ m/s^2 \ }

We get the flea's acceleration, i.e., 1,000 m/s².

<h3>Learn more</h3>
  1. About scientific notation brainly.com/question/7263463
  2. Finding the mass of substance brainly.com/question/4053884
  3. Converting in cubic brainly.com/question/1446243

Keywords: flea, when jumping, rapidly extends its legs, take-off speed, initial velocity, distance, acceleration, uniformly accelerated motion, convert

5 0
3 years ago
Read 2 more answers
PLEASE HURRY I WILL GIVE THE BRAINLYEST TO THE PERSON WHO GETS THIS CORRECTLY
Naily [24]

Answer:

3 ≤11 ≤ 11

Step-by-step explanation:

3x-4 = 2x +1

3x-5 = 2x

x-5 = 0

x= 5

3 ≤11 ≤ 11

5 0
3 years ago
The original scale factor of the drawing of a squirrel swimming pool is 1 / 90 in the event of the original drawing measured to
lawyer [7]
Yup Jake is correct ^-^
3 0
4 years ago
A sum of money is deposited in a bank which offers a simple interest rate of 0.325% per annum. At
frosja888 [35]

Answer:

50.000

Step-by-step explanation:

the formula to get ther is the following:

X + ( X * \frac{0.325}{100} * 4 ) = 50.650

X is the initial amount of money you need to find

4 are the years of interests

So, If you have interests, it means that some money will be added to yours. But how much?

The problem says that every year 0.325% of your initial amount will be added, so you will calculate that amount( X * \frac{0.325}{100}) and you multiply it by four.

All this added to your initial amount will be the final number you have 50.560

6 0
3 years ago
Ayo can y’all help? No rush but it’s 25 points with brainliest
Sergio [31]

You know the answer is the third choice (C) because 7^2 is 49 and 8^2 is 56, the two closest squared numbers to 54.

49 < 54 < 56

The square root of 54 is  roughly 7.4

I hope that helps :)

8 0
3 years ago
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