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Tanzania [10]
3 years ago
10

Simplify

7B3%7D%5E%7B9%7D%20%20%5Cdiv%20%7B27%7D%5E%7B9y%7D%20" id="TexFormula1" title=" {3}^{7y} \times {81}^{8y} \times {3}^{9} \div {27}^{9y} " alt=" {3}^{7y} \times {81}^{8y} \times {3}^{9} \div {27}^{9y} " align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
Papessa [141]3 years ago
5 0

Answer

3^{7y} * 81^{8y} * 3^9  * 27^{-9y} = 3^{7y} * (3^4)^{8y} * 3^9  *(3^3)^{-9y}          

                                =3^{7y} * (3)^{32y} * 3^9  *(3)^{-27y}\\\\=3^{7y +32y +9 -27y}\\\\=3^{12y+9}

Tip :    

\frac{1}{27^{9y}}  = 27^{-9y} = (3^3)^{-9y} = 3^{-27y}                          

Rashid [163]3 years ago
5 0

Answer:

3^{12y+9}

Step-by-step explanation:

→ Convert all integers to base 3

3^{7y} *3^{4*8y}*3^{9} /3^{3*9y}

→ Simplify

3^{7y}*3^{32y}  *3^{9} /3^{27y}

→ Collect all the like terms

3^{12y+9}

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Step-by-step explanation:

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7 0
2 years ago
A(n-3)+8=bn solve for n
vfiekz [6]
N= 3a - 8
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a-b

- First you will use the distributive property for multiplication on the left side of the equation.
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5 0
4 years ago
30 POINTS PLEASE HELP! GIVING BRAINLIEST :)
Liono4ka [1.6K]

Answer:

45

Step-by-step explanation:

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Combine like terms

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Let x = 6

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45

8 0
3 years ago
Read 2 more answers
Factor: 10x^3-35x^2-12x+42<br><br> I'll give brainliest :) but please show all work.
alexandr402 [8]

Answer:

\left(2x-7\right)\left(5x^2-6\right)

Explanation:

\hookrightarrow\sf 10x^3-35x^2-12x+42

using associative property, separate

\hookrightarrow\sf \left(10x^3-35x^2\right)+\left(-12x+42\right)

take common term, factorise

\hookrightarrow\sf 5x^2\left(2x-7\right)-6\left(2x-7\right)

final answer

\hookrightarrow\sf \left(2x-7\right)\left(5x^2-6\right)

5 0
2 years ago
Read 2 more answers
Help idk how to do this :(
Natasha2012 [34]
A) 10,000 = 10^4
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4 years ago
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