Answer:
<h2>231cm²</h2>
Step-by-step explanation:
First, let's find the surface area of both the triangles
5x3=15
So, the surface area of the triangles is 15 sq.cm
Now, let's find the surface area of the base (large rectangle in the middle)
12x8=?
10x8=80
2x8=16
80+16=96
12x8=96
So, the surface area of the base, is 96sq.cm
Now, let's find the surface area of both of the side rectangles
12x5=60
60x2=120
So, the surface area of the two side rectangles is 120sq.cm
Now, let's find the total surface area by adding all of our answers.
120+96=216
216+15=231
<h2>
So hence, the surface area of this net is 231cm²</h2>
Answer:
This can not be properly answered, because we do not have the length of each trail.
The first step here will be find the length, in miles, for each of the four trails.
As students choose all four trails, the number of miles that each student will bike is equal to the addition of the lenght of the four trails.
Suppose this number is N.
So each student bike N miles, and the company donates $1.75 per mile. Then the amount of money that a single student is N times $1.75, or N*$1.75
Answer:
The goodness of fitness test χ²with significance of level ∝= 0.05 and 5 degrees of freedom is 11.07 (One tailed test )
Step-by-step explanation:
For n=6 the degrees of freedom will be n-1 = 5 .
The goodness of fitness test χ²with significance of level ∝= 0.05 and 5 degrees of freedom is 11.07 (One tailed test )
The critical region depends on ∝ and the alternative hypothesis
a) When Ha is σ²≠σ² the critical region is
χ² < χ²(1-∝/2)(n-1) and χ² > χ²(1-∝/2)(n-1) Two tailed test
( χ² < 0.83) and ( χ² > 0.83)
b) When Ha is σ²> σ² the critical region falls in the right tail and its value is
χ² > χ²(∝)(n-1) One tailed test {11.07 (One tailed test )}
c) When Ha is σ² <σ² the critical region will be entirely in the left tail with critical value
χ²(1-∝)(n-1) One tailed test (1.145)
Answer:
answer is -5
Step-by-step explanation:
Answer:
N(20) = T
Step-by-step explanation:
N = Amount of lawns
20 = payment per lawn
T= payment after N lawns
Lets say there were 2 lawns
2(20)=T
40$ for 2 lawns