Answer:
The probability that the total weight of the passengers exceeds 4222 pounds is 0.0018
Step-by-step explanation:
The Central limit Theorem stays that for a large value of n (21 should be enough), the average distribution X has distribution approximately normal with mean equal to 182 and standard deviation equal to 30/√21 = 6.5465. Lets call W the standarization of X. W has distribution approximately N(0,1) and it is given by the formula

In order for the total weight to exceed 4222 pounds, the average distribution should exceed 4222/21 = 201.0476.
The cummulative distribution function of W will be denoted by
. The values of
can be found in the attached file.

Therefore, the probability that the total weight of the passengers exceeds 4222 pounds is 0.0018.
In scientific notation, you must move the "invisible decimal point" until there is a one-digit number, sometimes followed by a decimal of more numbers. Then, how ever many digits you had to move it is the exponent to the number 10.
Example:
1200.
120.0
12.00
1.200
Since the decimal had to move 3 places, the scientific notation of this is:
1.2 • 10^3
In this question, the decimal must move 9 places left before resulting in 1.322.
So the answer, in scientific notation, is 1.322 • 10^9.
5 - x - 4 ≤ -3
1 - x ≤ -3
-x ≤ -4
x ≥ 4 is the answer
Answer:
She lands on 92.
Step-by-step explanation:
92=58+2+30+2
where she lands = 58+34
92 = 58 + 2x + y where x=2 and y=32