All categories

4 years ago

What is 1.3333333 as a fraction ?

Mathematics

2 answers:

denis23 [38]4 years ago

8 0

The answer is 1 3/9. The reason is because it repeats 3 so it would be 9 at the bottom.

Alex_Xolod [135]4 years ago

3 0

1 and 1/3 .............

You might be interested in

Officials project that between 2010 and 2050, the population of a certain city will drastically change. The model below gives th

MaRussiya [10]

Answer:

In the year 2010, the population of the city was 175,000

Step-by-step explanation:

If we rewrote this as a linear expression in standard form (it is linear, btw), it would look like this:

$P(t)=\frac{11}{2}t+175$

The rate of change, the slope of this line, is 11/2. If the year 2010 is our time zero (in other words, we start the clock at that year), then 0 time has gone by in the year 2010. In the year 2011, t = 1 (one year goes by from 2010 to 2011); in the year 2012, t = 2 (two years have gone by from 2010 to 2012), etc. If we plug in a 0 for t we get that y = 175,000. That is our y-intercept, which also serves to give us the starting amount of something time-related when NO time has gone by.

3 0

3 years ago

A Country Has A Goal To Build 12,000 bus stop shelters in 48 months. If the country builds 215 bus shelters each month, will it

dimaraw [331]

No because if you do the math if you do 215 x 48 in doesn't reach to 12000 at all.

6 0

4 years ago

A recent study focused on the number of times men and women send a WeChat message in a day. The information is summarized next.

Ratling [72]

Answer:

1)Null hypothesis: $\mu_{men}=\mu_{women}$

Alternative hypothesis: $\mu_{men} \neq \mu_{women}$

2) Two critical values are $z_{\alpha/2}=-2.58$ and $z_{1-\alpha/2}=2.58$

3) $z=-2.40$

4) $p_v =2*P(z$

5) Comparing the p value with the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we FAIL to reject the null hypothesis, and a would NOT be a significant difference in the mean number of times men and women send a Twitter message in a day.

Step-by-step explanation:

Data given and notation

$\bar X_{men}=23$ represent the mean for the sample men

$\bar X_{women}=28$ represent the mean for the sample women

$\sigma_{men}=5$ represent the population standard deviation for the sample men

$\sigma_{women}=10$ represent the population standard deviation for the sample women

$n_{men}=25$ sample size for the group men

$n_{women}=30$ sample size for the group women

t would represent the statistic (variable of interest)

$\alpha=0.01$ significance level provided

1）Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the means for the two groups are different, the system of hypothesis would be:

Null hypothesis: $\mu_{men}=\mu_{women}$

Alternative hypothesis: $\mu_{men} \neq \mu_{women}$

Since we know the population deviations for each group, for this case is better apply a z test to compare means, and the statistic is given by:

$z=\frac{\bar X_{men}-\bar X_{women}}{\sqrt{\frac{\sigma^2_{men}}{n_{men}}+\frac{\sigma^2_{women}}{n_{women}}}}$ (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

2）Determine the critical value(s).

Based on the significance level $\alpha=0.01$ and $\alpha/2=0.005$ we can find the critical values with the normal standard distribution, we are looking for values that accumulates 0.005 of the area on each tail on the normal distribution.

For this case the two values are $z_{\alpha/2}=-2.58$ and $z_{1-\alpha/2}=2.58$

3) Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

$z=\frac{23-28}{\sqrt{\frac{5^2}{25}+\frac{10^2}{30}}}}=-2.40$

4）What is the p-value for this hypothesis test?

Since is a bilateral test the p value would be:

$p_v =2*P(z$

5）Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we FAIL to reject the null hypothesis, and a would NOT be a significant difference in the mean number of times men and women send a Twitter message in a day.

4 0

3 years ago

Determine whether the pair of triangles are similar.

den301095 [7]

Answer:

Option 4

Step-by-step explanation:

3 0

4 years ago

Read 2 more answers

(a+b)2 ;a=1/2 and b=2

FrozenT [24]