Answer:
The surface area of the triangular prism is
.
Step-by-step explanation:
The surface area of any prism is the total area of all its sides and faces. A triangular prism has three rectangular sides and two triangular faces.
An equilateral triangle is a triangle with all three sides of equal length.
To find the surface area, the area of each face is calculated and then add these areas together.
The formula
is used to find the area of the triangular faces, where A = area, b = base, and h = height.
The formula
is used to find the area of the three rectangular side faces, where A = area, l = length, and w = width.
The surface area of the triangular faces is:

The surface area of the three rectangular side faces is:

The surface area of the triangular prism is
.
B...................................
For each of these problems, all you need to do is isolate the variable. I’ll do the first few to help you out :)
32) 7 = -12 + e
Add 12 to both sides to isolate e.
19 = e
35) (r + 4) + 2 = 1
Subtract 2 from both sides.
r + 4 = -1
Subtract 4 from both sides to isolate r.
r = -5
38) -2 + (1 + p) = 5
Add 2 to both sides.
1 + p = 7
Subtract 1 from both sides to isolate p.
p = 6.
So essentially, all you need to do is add and subtract from each side to isolate the variable given in each problem. :)
Extra tip: In order to get rid of a number on one side (to isolate a variable), you must perform the opposite operation. For example, -2 + x = 1. In order to isolate x, add 2 to the left side to get rid of it, as well as adding it onto the right side so that it is not erased completely to get x=3)
Answer:
it says x-intercepts, multiplicity, and factors. or ar you talking about the graph on the right? well be more specific next time
He can measure the height in inches or centimeters.
The time can be measured in hours.
He can take a measurement of the height in inches or centimeters at a starting point. Then he can let snow fall for a certain number of hours.
Then he divides the height in inches or centimeters by the number of hours to find the rate in inches per hour or centimeters per hour.