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3 years ago

5

A plane was flying 4,000 feet in the sky,and a skydiver jumped out.After he had fallen 2,000 feet,he was just 550 feet higher th

an the top of the Sears Tower.How tall is the Sears Tower?

1 answer:

masha68 [24]3 years ago

8 0

Answer:

1450feet is the height of the tower

pls mark brainliest- please

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Steve drove at a constant rate to the beach for a vacation. In the equation below, t is the time in hours it took Steve to drive

hjlf

Could you please provide the equation and the rest of the question?

7 0

3 years ago

If 10% of x is 30, what is 23% of x <br> A. 33<br> B. 46<br> C. 200<br> D. 230

aliina [53]

Answer:

69

Step-by-step explanation:

I'm mathematics, the word 'of' transfers into becoming 'times or Multiply'

Therefore, the expression can be rewritten as:

10/100 of x = 30

10x / 100 = 30

Cross Multiply the equation to solve for x

10x = 100 * 30

10x = 3000

x = 3000 / 10

x = 300

(Since we gotten the value of x as 300) let's find 23% of it.

Therefore,

23% of x, ( when x is 300)

= 23/100 * 300

= 23 * 3

= 69

(Well, although that's the workable solution, the option doesn't seen to tally)

Maybe you check the source, but am certain about the Solution.

Let's keep learning, maths is fun !

3 0

3 years ago

Read 2 more answers

In 1981, the Australian humpback whale population was 350 and has increased at a rate of 14% each year since then.)

dimulka [17.4K]

Answer:

In 1981, the Australian humpback whale population was 350

Po = Initial population = 350

rate of increase = 14% annually

P(t) = Po*(1.14)^t

P(t) = 350*(1.14)^t

Where

t = number of years that have passed since 1981

Year 2000

2000 - 1981 = 19 years

P(19) = 350*(1.14)^19

P(19) = 350*12.055

P(19) = 4219.49

P(19) ≈ 4219

Year 2018

2018 - 1981 = 37 years

P(37) = 350*(1.14)^37

P(37) = 350*127.4909

P(37) = 44621.84

P(37) ≈ 44622

There would be about 44622 humpback whales in the year 2018

5 0

4 years ago

If the principal is $300 rate 3% time 4 years then what is the interest earned and the new balance

Tomtit [17]

Answer:

a) Interest earned = $36

New Balance = $336

b) Interest rate = 0.05 or 5%

New Balance = $517.5

c) time t = 5

New Balance = $612.5

d) Principal Amount = $675

New Balance = $783

Step-by-step explanation:

We are given:

a) Principal (P) = $300

Rate (r) = 3% or 0.03

Time (t)= 4 years

Interest earned = ?

The formula used is: $Simple \ Interest (I)= P\times r\times t$

Putting values and finding interest

$Simple \ Interest (I)= P\times r\times t\\Simple \ Interest (I)= 300\times 0.03\times 4\\Simple \ Interest (I)= 36$

So, Interest earned = $36

New Balance = Principal + Interest = 300+36 = $336

b) a) Principal (P) = $300

Rate (r) = ?

Time (t)= 3 years

Interest earned = 67.50

The formula used is: $Simple \ Interest (I)= P\times r\times t$

Putting values and finding rate

$Simple \ Interest (I)= P\times r\times t\\67.50= 450\times r\times 3\\67.50=1350\times r\\r=\frac{67.50}{1350}\\r=0.05 \ or \ 5\%$

So, Interest rate = 0.05 or 5%

New Balance = Principal + Interest = 450+67.50 = $517.5

c) Principal (P) = $500

Rate (r) = 4.5% or 0.045

Time (t)= ?

Interest earned = $112.50

The formula used is: $Simple \ Interest (I)= P\times r\times t$

Putting values and finding time

$Simple \ Interest (I)= P\times r\times t\\112.50= 500\times 0.045\times t\\112.50=22.5 \times t\\t=\frac{112.50}{22.5}\\t=5$

So, time t = 5

New Balance = Principal + Interest = 500+112.50 = $612.5

d) Principal (P) = ?

Rate (r) = 8% or 0.08

Time (t)= 2 years

Interest earned = 108.00

The formula used is: $Simple \ Interest (I)= P\times r\times t$

Putting values and finding Principal

$Simple \ Interest (I)= P\times r\times t\\108=P\times 0.08 \times 2\\108=P\times 0.16\\P=\frac{108}{0.16}\\P=675$

So, Principal Amount = $675

New Balance = Principal + Interest = 675+108 = $783

8 0

3 years ago

PLEASE HELP ME <br><br><br><br> Find the slope and y-intercept of the following graph.

Ronch [10]

The y-intercept is 2 and the Slope is 2/4 but if you simplify that, it will be 1/2.

8 0

3 years ago