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dsp73
3 years ago
11

Alguien tiene 13 años ​

Mathematics
2 answers:
Sergio039 [100]3 years ago
7 0
This is math section!
STatiana [176]3 years ago
7 0
This section is for math u need to go the language section
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85m+16m+43m=85m+43m+16m is an example of what mathematical property?
Drupady [299]

Answer:

Commutative Property

Step-by-step explanation:

Commutative property, changes the order of the addends does not change the sum

Ex)

16+45=45+16

3 0
3 years ago
Read 2 more answers
Ralph is an electrician. He charges an initial fee of $24, plus $33 per hour. If Ralph earned $189 on a job, how long did the jo
11111nata11111 [884]
Charge of Ralph:

Charge = $24  + $33 per hour

Let the time worked be = x.

For x hours, the cost = 33*x = 33x

Charge = 24 + 33x

24 + 33x = 189

33x = 189 - 24

33x = 165

x = 165/33

x = 5

The job took 5 hours.

I hope this helped
3 0
3 years ago
The number of nuts in a can of mixed nuts is found to be normally distributed, with a mean of 500 nuts and a standard deviation
timofeeve [1]

Answer:

z = -2.85

Step-by-step explanation:

Since the number of nuts per can is normally distributed:

Mean number of nuts (μ)= 500 nuts

Standard Deviation (σ)= 20 nuts

X = 443 nuts

For any given number of nuts X, the z-score is given by:

z=\frac{X-\mu}{\sigma} =\frac{443-500}{20}\\z= -2.85

The z-score for this can of nuts with 443 nuts is -2.85.

3 0
3 years ago
Read 2 more answers
−2⋅f(−6)−7⋅g(−7)=<br> what is the answerrr
Mrrafil [7]

Answer:

idk know dude I'm sorry

4 0
3 years ago
PLEASE HELP!!! Two towns are 1100 miles apart. A group of hikers starts from each town and walks down the trail toward each othe
Vinvika [58]

Answer:

2.54 miles/hr

2.04 miles/hr

Step-by-step explanation:

<u>Given: </u> Distance between the two towns = 1100 miles

Difference between speeds = \frac{1}{2} miles/hr

Total time when they meet = 240 hours

<u>To find:</u>

Let distance traveled by first group = x miles.

Now, the distance traveled by second group = (1100-x) miles/hr

The relation between Speed, Time and Distance is given as:

\text{Speed =} \dfrac{\text{Distance}}{\text{Time}}

Let speed of first group = S_1

S_1 = \dfrac{x}{240}

Let speed of second group = S_2

S_2 = \dfrac{1100-x}{240}

As per question, S_1 = S_2 + \frac{1}{2}

\dfrac{x}{240} = \dfrac{1100-x}{240} + \dfrac{1}{2}\\\Rightarrow \dfrac{x}{240} - \dfrac{1100-x}{240} = \dfrac{1}{2}\\\Rightarrow \dfrac{x-1100+x}{240} = \dfrac{1}{2}\\\Rightarrow 2x - 1100 = 120\\\Rightarrow 2x = 1220\\\Rightarrow x = 610 ft

Now,

S_1 = \dfrac{x}{240}

Putting value of x:

S_1 = \dfrac{610}{240}\\\Rightarrow S_1 = 2.54\ miles/hr

Similarly, putting value of x in S_2:

S_2 = \dfrac{1100-610}{240}\\\Rightarrow S_2=\dfrac{490}{240}\\\Rightarrow S_2 = 2.04\ miles/hr

8 0
3 years ago
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