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Katarina [22]
3 years ago
14

How would plot y=1/4x-4 on graph

Mathematics
1 answer:
zmey [24]3 years ago
6 0

Answer:

________________________

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Which is bigger 3/8 or 0.38
FinnZ [79.3K]
0.38 if you divide 100 by 8 you get 0.125 and when you multiply it by 3 you get 0.375. 0.38>0.375

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A bag contains 45 marbles of various colours. Lena draws 48 times, each time replacing the marble before drawing again. She gets
sergiy2304 [10]
I think the answer is c im not sure sorry
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Rewrite in simplest terms: -7(5v-10)-7v
Over [174]

Answer: -42v + 70

Step-by-step explanation: You’d multiply -7 with the figures in the brackets, then you’d group like terms then subtract -7v from -35v.

1. -35v + 70 - 7v

Negative multiplied by negative is a positive

2. -35v - 7v + 70

Group like terms

3. -42v +70

Subtract

Hope this was helpful

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2 years ago
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What are the factors of the expression? 3⋅(4r+y) Drag the factors of the term into the box.
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6 0
3 years ago
Gabriella is X years old her sister Felisha is 6 years older than she is their mother is twice as old is Felicia their aunt Tany
Makovka662 [10]

Hey!

Hope this helps...

~~~~~~~~~~~~~~~~~~~~~~~~

Let me lay down the Given, and than I'll solve the question...

<em>Felisha</em> is 6 years older than <em>Gabriella</em><em> - (y)</em>

<em>Their Mother</em> is 2 times older than <em>Felisha</em>

<em>Their Aunt (Tanya - [x] )</em> is X years older than <em>Their Mother</em>

<em /><u><em>We are solving for how old is Tanya? ...</em></u>

**I stated Gabriella with a y instead of an X so that the equation does not look confusing, feel free to replace my y with "<em /><em>Gabriella(X)</em>", when writing/typing your answer...

**When I use the variable <em>Z</em>, this is how many years Tanya is older than the Mother...


To find how many years Tanya is older than the Mother: Z = 2 * (6 + y)

Now... the answer is: X = (2 * (6 + y)) + Z

I stated it this way, because we have to add Felisha's and Gabriella's age first, and than your multiply that age <em>Total</em> by 2 to get the Mother's age...

3 0
2 years ago
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