Answer:
A farmer has enough food to feed 20 animals in his cattle for 6 days. How long would the food last if there were 10 more animals in his cattle? Here the number of animals and the number of days are in inverse proportion. Hence the food will last 4 days.
Answer:
216 cm³
Step-by-step explanation:
1/3x + 63 = 5/8x
subtract 1/3x from each side; (1/3x = 8/24x and 5/8x = 15/24x)
63 = 7/24x
7x = 63(24)
7x = 1512
x = 216
The given answer should be "3/2", its because "32" is not possible in anyway..
tan C = sin C / cos C
Where sin C = 3 / 3.61
And
cos C = 2 / 3.61
Now
tan C = (3 / 3.61) / (2 / 3.61) = (3 / 3.61) x (3.61 /
2) = 3 / 2
<span>Thus tan C is the correct choice. </span>
Hey there!
In order to multiply these polynomials together, you will take both terms of the first polynomial and multiply them by each term in the second polynomial. You can then combine any like terms to get your final answer.
(2x² – 5x)(4x² – 12x + 10)
2x² × 4x² = 8x⁴
2x² × –12x = –24x³
2x² × 10 = 20x²
–5x × 4x² = –20x³
–5x × –12x = 60x²
–5x × 10 = –50x
Write all of these terms together. You can rearrange the similar ones to be next to each other.
8x⁴ – 24x³ – 20x³ + 20x² + 60x² – 50x
Just add or subtract the terms to simplify, if they can be.
8x⁴ – 44x³ + 80x² – 50x
(8x⁴ – 44x³ + 80x² – 50x) will be your final answer.
Hope this helped you out! :-)
12/3 = 4 minutes
4 minutes per kilometre
4x7=28
28 minutes
