When they work together, they do 1/3 of the job in one hour.
(Bubba) + (Skeeter) = 1/3 job/hour
Subtract 'Bubba'
from each side: Skeeter = (1/3 job/hour) - (Bubba)
Bubba, working alone, does 1/8 of the job in one hour.
Skeeter = (1/3 job/hour) - (1/8 job/hour)
Can you subtract 1/8 from 1/3 ?
Before you can subtract, you'll need a common denominator.
I've got a nice one here . . . 24 .
1/3 = 8/24
1/8 = 3/24
Skeeter = (1/3 job/hour) - (1/8 job/hour)
= (8/24 job/hour) - (3/24 job/hour)
= 5/24 job/hour .
Skeeter mows at the rate of 5/24 field/hour.
The other way to look at that is: 24/5 hour/field = 4.8 hours .
Check:
Bubba: 1/8 field per hour = 0.125
Skeeter: 1/4.8 field per hour = 0.208333...
Together: (0.125 + 0.208333)
= 0.333... field per hour
= 3 hours/field . yay!
The slope is 3 use rise over run for this
I am not good with explianing but here is the answer: 9/5... Basic you subtract the when they ask for you to divid fractions 13-4.
Answer:
1/4
Step-by-step explanation:
Chances of getting tails out of all the numbers (including heads)
Totals numbers (including heads & tails): 12
Tails & Even Number: 3
3/12 simplified to 1/4
Answer:
1. CI = P (1 + 
)^ n - P
CI = A - P
Where P is Principal
R is interest rate
n is number of years
2. a. Semi annually - four times in a year
b. Monthly - two times in a year
c. annually - once in a year
Step-by-step explanation:
1. Money is said to be lent at compound interest , when the interest has become due at certain fixed period say, one year, half year, etc.., is given not paid to money lender, but is added to sum lent . The amount thus obtained become principal for next month and this process repeat until last period .
i.e CI = Final period - Initial period
or CI = A - P
or CI = P(1+ ) ^n - P
2. (a) Semi annually
A = P (1 + 
)^ n × 4
(b) Monthly
A = P (1 + 
) ^ n × 2
(c) Annually
A = P (1 + ) ^ n
