A = bh/2
2a = bh
2a/b = h
h = 2a/b
vertex = (3,- 5 )
given a quadratic in standard form : y = ax² + bx + c ( a ≠ 0 ), then
the x-coordinate of the vertex is
= - 
y = x² - 6x + 4 is in standard form
with a = 1, b = - 6 and c = 4, hence
= -
= 3
substitute this value into the equation for y- coordinate
y = 3² - 6(3) + 4 = 9 - 18 + 4 = - 5
vertex = (3, - 5 ) → second table
Answer:
y - 5 = 3(x - 4)
y - 5 = 3x - 12
y = 3x - 7
Step-by-step explanation:
Answer:
D) Distribute Property
Step-by-step explanation:
The student did Distribute property but they didn't mark it down.
To find Y you must divide two by each side, making y=-2
- I hope this helps :)