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3 years ago

10

Explain how modeling partial products can be used to find the products of greater numbers.

1 answer:

marin [14]3 years ago

5 0

Because when u add the smaller numbere it will be easier to add because you only have a little amount of numbers to add

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Which expression is equivalent to the expression shown? (5^4)2

marshall27 [118]

Answer:

5^8

Step-by-step explanation:

You multiply the exponents!!

7 0

3 years ago

Please this is due tonight!!! Express given logarithm in terms of a, b and c.

KATRIN_1 [288]

$\textit{Logarithm Change of Base Rule} \\\\ \log_a b\implies \cfrac{\log_c b}{\log_c a}\qquad \qquad c= \begin{array}{llll} \textit{common base for }\\ \textit{numerator and}\\ denominator \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \log_5(18)\implies \cfrac{\log(18)}{\log(5)}\implies \cfrac{\log(2\cdot 3\cdot 3)}{\log(5)}\implies \cfrac{\log(2)+\log(3)+\log(3)}{\log(5)}$

$\begin{cases} \log(3)=a\\ \log(2)=b\\ \log(5)=c \end{cases}\implies \cfrac{b+a+a}{c}\implies \cfrac{b+2a}{c} \\\\[-0.35em] ~\dotfill\\\\ \log_5^2(18)\implies [\log_5(18)]^2\implies \left( \cfrac{b+2a}{c} \right)^2\implies \cfrac{(b+2a)^2}{c^2} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \cfrac{b^2+4ab+4a^2}{c^2}~\hfill$

8 0

3 years ago

9. Write the equation of a line going<br>through the points (9, -2) and (-3,2).

hammer [34]

I dont know if it needs to be in slope intercept or general form so i'll put it in both for you

Answer:

Slope intercept form- Y = -1/3x + 1

General form- 1/3x + Y = 1, or, 1/3x + Y - 1 = 0

6 0

4 years ago

A chemist is using 351 milliliters of a solution of acid and water. If 14.1% of the solution is acid, how many milliliters of ac

stepan [7]

49.491 millimeters of acid is present

<em><u>Solution:</u></em>

Given that, chemist is using 351 milliliters of a solution of acid and water

14.1% of the solution is acid

To find: Milliliters of acid present

From given statement,

Solution of acid and water = 351 ml

14.1% of the solution is acid, which means that 14.1 % of 351 ml is acid

Therefore,

Milliliters of acid present = 14.1 % of 351 ml

Here "of" means multiplication

Therefore,

$\text{ Milliliters of acid present } = 14.1 \% \times 351$

$\rightarrow 14.1 \% \times 351\\\\\rightarrow \frac{14.1}{100} \times 351\\\\\rightarrow 0.141 \times 351 = 49.491$

Thus 49.491 millimeters of acid is present

6 0

4 years ago

The object below was made by placing a cone on top of a cylinder. The base of the cone is congruent to the base of the cylinder.

krok68 [10]

Answer:

Part 1) The volume of the object is $32\pi\ cm^{3}$ or $100.48\ cm^{3}$

Part 2) see the procedure

Step-by-step explanation:

Part 1) What is the volume, in cubic centimeters, of the object?

we know that

The volume of the object is equal to the volume of the cylinder plus the volume of the cone

<u>Find the volume of the cone</u>

The volume of the cone is equal to

$V=\frac{1}{3}\pi r^{2} h$

we have

$r=4/2=2\ cm$ -----> the radius is half the diameter

$h=3\ cm$

substitute the values

$V=\frac{1}{3}\pi (2^{2})(3)=4\pi\ cm^{3}$

<u>Find the volume of the cylinder</u>

The volume of the cylinder is equal to

$V=\pi r^{2} h$

we have

$r=4/2=2\ cm$ -----> the radius is half the diameter

$h=(10-3)=7\ cm$

substitute the values

$V=\pi (2^{2})(7)=28\pi\ cm^{3}$

Part 2) Then explain how you found the volume of the total shape

The volume of the total shape is equal to the volume of the cylinder plus the volume of the cone

$4\pi\ cm^{3}+28\pi\ cm^{3}=32\pi\ cm^{3}$ ------> exact value

Find the approximate value of the volume

assume $\pi=3.14$

$32(3.14)=100.48\ cm^{3}$

4 0

4 years ago