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Novay_Z [31]
3 years ago
14

Which are NOT true for solving equations? Select ALL that apply.

Mathematics
1 answer:
enot [183]3 years ago
3 0

Answer:

d, To undo addition, you can use multiplication

Step-by-step explanation:

a, To remove a whole number next to the variable, multiply both sides by that number

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I have a diameter of 6in how do i get my circumference step by step?
avanturin [10]
Equation: C=dπ
               C=6·3.14
               C=18.84
           answer^^^

6 0
3 years ago
Write the values that make the denominators zero. then solve the equation?
Olin [163]

Answer:

  denominators are zero for x=1

  there is no solution

Step-by-step explanation:

We suspect your equation is supposed to be ...

  10/(5x -5) +1/5 = 2/(x -1) . . . . . parentheses are required on denominators

The denominators will be zero for x=1.

This version of the equation has no solution. It simplifies to ...

  2/(x-1) + 1/5 = 2/(x -1)

  1/5 = 0 . . . . . subtract 2/(x-1) from both sides

There is no value of x that will make this equation true.

_____

<em>Alternative interpretation</em>

The way your equation is written, it must be interpreted according to the order of operations to be ...

  (10/5)x -5 +1/5 = (2/x) -1 . . . . x=0 makes the denominator zero

  2x -3.8 = 2/x

  2x^2 -3.8x = 2 . . . . multiply by x

  2(x^2 -1.9x +.95^2) = 2 +2(0.95^2)

  (x -0.95)^2 = 1.9025

  x = 0.95 ± √1.9025 ≈ {-0.4293, 2.3293}

4 0
3 years ago
Someone help me plz???
svetoff [14.1K]

Answer:

12ft

Step-by-step explanation:

Hope I helped!

May you give me brainliest if it is right?

8 0
3 years ago
What is the number sentence of 34 using addition
EleoNora [17]
If You mean A sum to write here's one :
31+3
5 0
3 years ago
Read 2 more answers
The sides of a right triangle are x, x+21, and x+27. what is the length of the hypotenuse
mina [271]
Answer: 51 uinits

The three numbers are x , x + 21 and x + 27. 
The greatest of the 3 numbers is x + 27, so x + 27 has to be the hypotenuse.

----------------------------------------------
Pythagoras Theorem
----------------------------------------------

a² + b²  = c²

x² + (x+21)² = (x+27)²

x² + x² + 42x + 441 = x² + 54x + 729

x² - 12x -288 = 0

(x - 24)(x + 12) = 0

x = 24 or x = -12 (rejected, length cannot be negative)

----------------------------------------------
Find hypotenuse
----------------------------------------------
 Hypotenuse = x + 27 = 24 + 27 = 51 units

-----------------------------------------------
Answer: 51 units
----------------------------------------------

3 0
3 years ago
Read 2 more answers
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