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3 years ago

Which are NOT true for solving equations? Select ALL that apply.

Mathematics

1 answer:

enot [183]3 years ago

3 0

Answer:

d, To undo addition, you can use multiplication

Step-by-step explanation:

a, To remove a whole number next to the variable, multiply both sides by that number

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27/64A bottled water company has designed a new cup for its dispenser. The cup will be a right circular cone with a three-inch r

tankabanditka [31]

Answer:

9.86 inches

Step-by-step explanation:

Given:

The cup will be a right circular cone with:-

Radius, r = 3 inches

Volume of cone = 93 cubic inches

Height of the cup, h = ?

Solution:

<u>By using :-</u>

<u /> $Volume\ of\ right\ circular\ cone=\frac{1}{3} \pi r^{2} h$

$93 =\frac{1}{3} \times\frac{22}{7} \times3\times3\times h\\ \\ 93=\frac{198}{21} h\\ \\ 93=9.43h$

By dividing both sides by 9.43

$\frac{93}{9.43} =\frac{9.43h}{9.43} \\ \\ 9.86\ inches=h$

Thus, the cup need to be 9.86 inches taller to hold 93 cubic inches of water.

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3 years ago

How do you eliminate the fractions on this to solve by elimination ????????

Alja [10]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

Reflect the triangle in the mirror line.

vredina [299]

Answer:

I can't include a picture but it will be the same shape except it will be flipped over and will look a bit like differently angled packman with the back of the mouth apart the same distance, with the mouth "pointier" part of it one line away from the red line from the other side.... Oof sorry if this didn't help, I tried my best...

Step-by-step explanation:

From the "point" of the blue triangle, go diagonally SE 2 spaces. From there, draw a straight line to the right for 3 spaces. From there, draw upwards two spaces, and then connect those two lines into a triangle.

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3 years ago

Which types of music were chosen by 40% of the people surveyed?<br> please help me thank you!!!

erma4kov [3.2K]

Country and Jazz

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2 years ago

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A fair die is rolled 12 times. the number of times an even number occurs on the 12 rolls has

bonufazy [111]

Answer:

Step-by-step explanation:

For a fair die, there are six likely options; 1, 2, 3, 4, 5, and 6

the probability of a even number is 3/6 = 0.5

Since the results of the die roll is independent and each trial is mutually exclusive, the distribution to explain the probability of occurrence will follow a binomial distribution such that n is the number of trials

x = number of successful throws

therefore for a Binomial distribution where

P(X =x) = nCx . P^x . (1-P)^ (n-x)

since p = 0.5, and n = 12, the distribution follows

P(X = x) = 12Cx . 0.5^x . (1 - 0.5)^(12- x)

= 12Cx . 0.5^x . 0.5)^(12- x)

where x = (0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12)

since we are interested in the probability of the number of times an even number occurs

it can occur either as P(X = 0), P(X =1), P(X =2), P(X =3), P(X =4), P(X =5), P(X =6), P(X =7), P(X =8), P(X =9), P(X =10), P(X =11), and P(X =12)

For no even number in 12 rolls,

P(X = 0) = 12C0 . 0.5^0 . 0.5^(12- 0) = 0.000244

For one even number in 12 rolls,

P(X = 1) = 12C1 . 0.5^1 . 0.5^(12- 1) = 0.002930

For two even number in 12 rolls,

P(X = 2) = 12C2 . 0.5^2 . 0.5^(12- 2) = 0.016113

For three even number in 12 rolls,

P(X = 3) = 12C3 . 0.5^3 . 0.5^(12- 3) = 0.053711

For four even number in 12 rolls,

P(X = 4) = 12C4 . 0.5^4 . 0.5^(12- 4) = 0.120850

For five even number in 12 rolls,

P(X = 5) = 12C5 . 0.5^5 . 0.5^(12- 5) = 0.193359

For six even number in 12 rolls,

P(X = 6) = 12C6 . 0.5^6 . 0.5^(12- 6) = 0.225586

For seven even number in 12 rolls,

P(X = 7) = 12C7 . 0.5^7 . 0.5^(12- 7) = 0.193359

For eight even number in 12 rolls,

P(X = 8) = 12C8 . 0.5^8 . 0.5^(12- 8) = 0.120850

For nine even number in 12 rolls,

P(X = 9) = 12C9 . 0.5^9 . 0.5^(12- 9) = 0.053711

For ten even number in 12 rolls,

P(X = 10) = 12C10 . 0.5^10 . 0.5^(12- 10) = 0.016113

For eleven even number in 12 rolls,

P(X = 11) = 12C11 . 0.5^11 . 0.5^(12- 11) = 0.002930

For twelve even number in 12 rolls,

P(X = 12) = 12C12 . 0.5^12 . 0.5^(12- 12) = 0.000244

Final test summation[P(X)] = 1

i.e.

P(X = 0) + P(X =1) + P(X =2) + P(X =3) + P(X =4) + P(X =5) + P(X =6) + P(X =7) + P(X =8) + P(X =9) + P(X =10) + P(X =11) + P(X =12) = 1

Hence since 0.000244 + 0.002930 + 0.016113 + 0.053711 + 0.120850 + 0.193359 + 0.225586 + 0.193359 + 0.120850 + 0.053711 + 0.016113 + 0.002930 + 0.000244 = 1.000000,

the probability value stands

7 0

3 years ago