Which are NOT true for solving equations? Select ALL that apply.

Mathematics

1 answer:

enot [183]3 years ago

3 0

Answer:

d, To undo addition, you can use multiplication

Step-by-step explanation:

a, To remove a whole number next to the variable, multiply both sides by that number

You might be interested in

Six identical squares are cut from the corners and edges of an 80 cm by 50 cm cardboard rectangle. the remaining piece is folded

Anna11 [10]

Check the picture.

let the length of a side of each of the squares removed be x.

The box formed will have dimensions: 80-2x, 50-2x, x(the height)

So the volume can be expressed as a function of x as follows:

f(x)=(80-2x)(50-2x)x= $[4000-160x-100x+4 x^{2} ]x=(4 x^{2}-260x+4000)x$

so $f(x)=4 x^{3}-260x^{2}+4000x$

the solutions of f'(x)=0 gives the inflection points, so the candidates for maxima points,

$f'(x)=12x^{2}-520 x +4000=0$

solving the quadratic equation, either by a calculator, graphing software, or by other algebraic methods as the discriminant formula, we find the solutions

x=10 and x=33.333

plug in f(x) these values to see which greater:

$f(10)=(80-20)(50-20)10=60*30*10=18000$ cm cubed

$f(33.333)=(80-66.666)(50-66.666)33.333=$ which is negative because (50-66.666)<0

Answer: 18000 cm cubed

5 0

3 years ago

Read 2 more answers

Write a for loop that assigns summedvalue with the sum of all odd values from 1 to usernum. assume usernum is always greater tha

Lapatulllka [165]

// Input value is usernum.
// This code snippet sums 1 + 3 + 5 + ... + usernum
// The answer is stored in the variable summedvalue.

N = (int) (usernum+1)/2; // maximum number of integers to be summed
int *v = malloc(N*sizeof(int)); // allocate storage for array v

// Calculate the number of loop counts and assign array v..
count = 0;
k = 1;
while (1) {
if (k>usernum) { // do not extend v beyond usernum
break;
}
v(count) = k; // assign an odd integer to v, including usenum
count++;
k += 2; // k is an odd number
if k>usernum { // handle usernum as odd or even
k = usernum;
}
}
n = count; // the size of array v.

// Calculate the sum in a for loop
summedvalue = 0; // initialize summedvalue
for (i=0; i<=n; i++) {
summedvalue += v(i);
}

5 0

3 years ago

A stockholder owns 381.881 shares. By the end of the year, he had increased his number of shares by 14.814. What’s the new total

beks73 [17]

Answer:

438.453 shares

Step-by-step explanation:

From my understanding, the question says that the shares were increased by 14.814%.

Therefore, we have to calculate the increase

Step 1: Calculate the increase

Previous shares : 381.881

Increase : 14.814%

Increase = 381.881 x 14.814% = 56.572

Step 2: Calculate the new total shares

New shares = 381.881 + (381.881 x 14.814%)

New shares = 381.881 + 56.572

News shares = 438.453

Therefore, the new total shares owned by the stockholder are 438.453 shares.

8 0

3 years ago

Three times a number (n) is 36 less than five times the number (n). What is the number?

rodikova [14]

Answer:

Step-by-step explanation:

To find the number, write an algebraic equation with the given information. Let the variable n represent the unknown number.

Now, break it by parts - "three times a number" would be $3n$ . The "is" means that it equals something, giving us $3n =$ . "36 less than 5 times the number" would be subtracting 36 from whatever 5 times the number is: $5n -36$ . So, put it all together and it is $3n = 5n-36$ .