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Irina-Kira [14]
3 years ago
15

What is an equation of the line that passes through point (5,-8) and is parallel to the line x+y=7

Mathematics
1 answer:
Igoryamba3 years ago
4 0

Answer:

The line given is equal to y=-x+7 (Through rearranging)

To find the new line, we substitute the given coordinates (5,8) in the equation without the given y-intersect (+7):

-8=-5+c

c=-3

The line parallel to x+y=7 that passes through the point (5,-8) is y=-x-3

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murzikaleks [220]

Answer:

35

Step-by-step explanation:

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A circle is drawn within a square as shown.
Vinil7 [7]
<h3>Area of shaded region is 21.5 square centimeter</h3>

<em><u>Solution:</u></em>

The area of the shaded region is equal to the area of the square minus the area of the circle

<em><u> Find the area of the square</u></em>

Area\ of\ square = a^2

Where, "a" is the length of each side

From given figure in question,

a = 10 cm

Area\ of\ square = 10^2\\\\Area\ of\ square = 100\ cm^2

<em><u>Find the area of circle </u></em>

The area of the circle is given as:

Area\ of\ circle = \pi r^2

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<em><u>Find the area of the shaded region</u></em>

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Thus area of shaded region is 21.5 square centimeter

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=solve%20%3A%20%20-%20%20%5C%5C%20%20%5C%5C%20%20%2810%20%7B%7D%5E%7B2%7D%20%20-%206%20%7B%7D%5
o-na [289]

\longrightarrow{\blue{64}} 

\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}

= (10 {}^{2} - 6 {}^{2} )

= [(10 \times 10) - (6 \times 6)]

= (10 0- 36)

= 64

\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35ヅ}}}}}

4 0
3 years ago
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When solving negative one over five(x − 25) = 7, what is the correct sequence of operations?
Stells [14]
The answer is simply A
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3 years ago
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