69.6 is the answer to ur question
What is the rest of the question and you will probably have to multiply
The triangle NET is an <em>isosceles</em> triangle as <u>ET</u> ≅ <u>TN</u> and ET = TN < EN given the condition that BEST is a <em>cyclic</em> quadrilateral.
<h3>How to determine the existence of an isosceles triangle</h3>
In this question we must apply <em>geometric</em> properties of angles and triangles to determine that the triangle NET is an <em>isosceles</em> triangle. <em>Isosceles</em> triangles are triangles with two sides of equal length. In addition, we must apply the geometric concept of proportionality.
Now we proceed to prove the existence of the isosceles triangle:
- <u>BE</u> ≅ <u>SN</u> Given
- ET is the bisector of ∠BES Given
- ET/ES = ET/EB Definition of proportionality
- ES = EB (3)
- <u>ES</u> ≅ <u>EB</u> Definition of congruence
- <u>ET</u> ≅ <u>TN</u> SSS Theorem/Result
Therefore, the triangle NET is an <em>isosceles</em> triangle as <u>ET</u> ≅ <u>TN</u> and ET = TN < EN given the condition that BEST is a <em>cyclic</em> quadrilateral. 
To learn more on isosceles triangles, we kindly invite to check this verified question: brainly.com/question/2456591
Answer:
PartA
P = 4a
Part B
60 = P fence + 2a
60 = 6a
Part C
40
Step-by-step explanation:
We are building a fence so we are finding perimeter.
Adding the 3 sides
P = a+b+a
P = 2a+b
It is twice as long as it is wide
b= 2a
Replace in the equation for perimeter
P = 2a+(2a)
P = 4a
Part B
We know the perimeter is 60 for the entire backyard
The perimeter of the backyard is the fence plus the longer side
60 = P fence + b
Replacing b
60 = P fence + 2a
We know the equation for the perimeter of the fence is
60 = 4a + 2a
Combing like terms
60 = 6a
Part C
Solve for a and b
60 = 6a
Divide each side by 6
60/6 = 6a/6
10 =a
P fence = 4a
P = 4(10) = 40
Answer:
2/3
Step-by-step explanation:
In the 5-minute interval between 7:00 and 7:05, a train to B is the first to arrive. In the 10-minute interval between 7:05 and 7:15, a train to A is the first to arrive. That is, in any 15-minute interval, the probability is 10/15 = 2/3 that a train to A is the first to arrive.
The 1-hour interval between 7 A.M. and 8 A.M. is an integer number of such intervals, so ...
2/3 of the time, he or she will go to destination A.