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BigorU [14]
4 years ago
14

13. NBT.4

Mathematics
1 answer:
slava [35]4 years ago
7 0
B 0.05 since the thousandth digit is higher than 5, it needs to be rounded up.
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How many ways are there to select a 5-card hand from a regular deck such that the hand contains at least one card from each suit
Snezhnost [94]

Answer:

There are 685464 ways of selecting the 5-card hand

Step-by-step explanation:

Since the hand has 5 cards and there should be at least 1 card for each suit, then there should be 3 suits that appear once in the hand, and one suit that apperas twice.

In order to create a possible hand, first we select the suit that will appear twice. There are 4 possibilities for this. For that suit, we select the 2 cards that appear with the respective suit. Since there are 13 cards for each suit, then we have {13 \choose 2} = 78 possibilities. Then we pick one card of all remaining 3 suits. We have 13 ways to pick a card in each case.

This gives us a total of 4*78*13³ = 685464 possibilities to select the hand.

6 0
3 years ago
The next term of the arithmetic sequence 39,60,81,102,123.....is
Rasek [7]
It is 144 just add 21
6 0
3 years ago
Read 2 more answers
Find the missing measurement. Use 3.14 for it.*
Anarel [89]

Answer:

452.16 mm squared is a correct answer.

Sure!

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3 0
3 years ago
One hundred times the quantity five plus three
Maru [420]
Five-5

three-3

"the quantity five plus three" (5 + 3) 

"one hundred times the quantity ..." means  100 (5 + 3)   

now just solve 100(5+3) 

solve the parentheses first (5+3) = 8

Now you are left with 100(8) or 100*8

when you solve your answer is 800
3 0
3 years ago
WILL<br><br><br> GIVE <br><br> BRAINLIST <br><br> ANSWERS
enot [183]

Answer:

-10

-I-8I = -8

-(-2) = 4

I-11I  = 11

5² = 25

Answer: -10, -8, 4, 11, 25

6 0
3 years ago
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