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MrRissso [65]
3 years ago
14

Solve for x please help

Mathematics
1 answer:
34kurt3 years ago
4 0

Answer:

x = 9

Step-by-step explanation:

By remote exterior angle theorem:

(12x + 14)\degree = (1 + 5x) \degree+ 76 \degree \\ 12x + 14 = 1 + 5x + 76 \\ 12x - 5x = 77 - 14 \\ 7x = 63 \\x =  \frac{63}{7}  \\ \huge \red{ \boxed{ x = 9}}

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It is known that 10 workers take 30 days to complete a project. They start working and the next day one quits. the next another,
Burka [1]

Answer:

<h3>5 workers finish this work in 60 days</h3>

Step by step explanation:

The problem tells us that at the end of the day, there are only 5 workers left, which we must find how many days it takes to finish said work.

We start by finding the type of proportionality we have.

<em>In this case, we have that the more workers there are, they will finish that work in less time, and the fewer workers there are, the longer it will take to finish the work. This is the inverse proportionality, to more less, to less more.</em>

We have only 5 workers left.

In the first case there are 10 workers, and in the second case there are 5 workers left. We find the relationship between the workers in the second case among the workers in the first case.

<h3>Ratio = 5 workers / 10 workers = 1/2</h3>

We see that the time is found by dividing the number of days in which the 10 workers finish the work, by 1/2.

As we know, dividing two fractions is the SAME as multiplying by the inverse fraction.

\rm 30 * 2/1 \: = 60 \: days

By so

<h3>5 workers finish this work in 60 days</h3>
5 0
2 years ago
In this question, i is a unit vector due east and j is a unit vector due north. A cyclist rides at a speed of 4 m/s on a bearing
d1i1m1o1n [39]

<u>Answer:</u>

a) 1.04i + 3.86j

b) magnitude = 8; bearing = 302.7°

<u>Step-by-step explanation:</u>

a)

The  first diagram represents the velocity vector of the cyclist.

To express this vector in the form xi + yj, we have to find the components of the vector in the horizontal (i) and vertical (j) directions.

If we consider the horizontal component of the vector to be x, and the vertical component to be y, then:

• horizontal component ⇒ sin (15^{\circ}) = \frac{x}{4}

                                       ⇒ x = 4\space\ sin(15^{\circ})

                                       ⇒ x \approx \bf 1.04

• vertical component ⇒ cos(15^{\circ}) = \frac{y}{4}

                                   ⇒ y = 4 \space\ cos(15^{\circ})

                                   ⇒ y \approx \bf 3.86

Now that we have the values of both the horizontal and vertical component, we can write the vector in the form of xi + yj:

vector ⇒ 1.04i + 3.86j

b)

The second diagram shows the first vector (red), the second vector (blue), and the resultant vector <em>v</em> (black). The dashed lines represent the components of the respective vectors.

To add two vectors given their magnitudes and direction, we have to add their components.

In order to find the horizontal and vertical components of the given vectors, we can use a method similar to that used above, so that:

○ For the first vector (magnitude 6):

• horizontal component ⇒ x = 6 \space\ sin (60^{\circ})

                                       ⇒ \bf 5.2

• vertical component ⇒ y = 6 \space\ cos(60^{\circ})

                                   ⇒ y = \bf 3

○ For the second vector (magnitude 2):

• horizontal component ⇒ x = 2 \space\ cos (40^{\circ})

                                       ⇒ \bf 1.5

• vertical component ⇒ y = 2 \space\ sin(40^{\circ})

                                   ⇒ \bf 1.3

Now we can add the respective components together:

v = 5.2i + 3j  +  1.5i + 1.3j

 ⇒ (5.2 + 1.5)i + (3 + 1.3)j

 ⇒  6.7i + 4.3j

∴ Magnitude of v ⇒ |v| = \sqrt{(6.7)^2 + (4.3)^2}

                             ⇒ |v| \approx \bf 8

To find the bearing of <em>v</em>, we have to first calculate the angle marked \alpha:

tan \alpha = \frac{4.3}{6.7}

⇒ \alpha = tan^{-1}(\frac{4.3}{6.7})

⇒ \alpha = \bf 32.7^{\circ}

∴ Bearing = 270° + 32.7°

                = 302.7°

8 0
2 years ago
The cash operating expenses of the regional phone companies during the first half of 1994 were distributed about a mean of $29.9
soldi70 [24.7K]

Answer:

The percentage of regional phone companies whose operating expenses were closer to the mean than the operating expenses of Company A were to the mean is 73%.

Step-by-step explanation:

The Company A's operating expenses were $27.00. This is $2.93 less than the regional mean.

\Delta E=29.93-27.00=2.93

The companies whose operating expenses are closer to the mean are the ones that have expenses $2.93 below or above the mean.

The fraction of companies that are closer to the mean is equal to the proability of having expenses between those two limits:

z_1=(M-\mu)/\sigma=-2.93/2.65=-1.105\\\\z_2=+1.105

P(|z|\leq1.105)=P(z\leq 1.105)-P(z

4 0
3 years ago
HELP PLEASE ILL GIEV CORRECT ANSWER BRAINLY!
BigorU [14]

Answer:

number 3

Step-by-step explanation:

i took the test

8 0
3 years ago
Read 2 more answers
Plz help will be thanked and will pick out brainly
Brums [2.3K]
The answer is 32
Hope this helps:D
have a great rest of a brainly day!
5 0
3 years ago
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