Answer:
0.153
Explanation:
We know the up-thrust on the fish, U = weight of water displaced = weight of fish + weight of air in air sacs.
So ρVg = ρ'V'g + ρ'V"g where ρ = density of water = 1 g/cm³, V = volume of water displaced, g = acceleration due to gravity, ρ'= density of fish = 1.18 g/cm³, V' = initial volume of fish, ρ"= density of air = 0.0012 g/cm³ and V" = volume of expanded air sac.
ρVg = ρ'V'g + ρ"V"g
ρV = ρ'V'g + ρ"V"
Its new body volume = volume of water displaced, V = V' + V"
ρ(V' + V") = ρ'V' + ρ"V"
ρV' + ρV" = ρ'V' + ρ"V"
ρV' - ρ"V' = ρ'V" - ρV"
(ρ - ρ")V' = (ρ' - ρ)V"
V'/V" = (ρ - ρ")/(ρ' - ρ)
= (1 g/cm³ - 0.0012 g/cm³)/(1.18 g/cm³ - 1 g/cm³)
= (0.9988 g/cm³ ÷ 0.18 g/cm³)
V'/V" = 5.55
Since V = V' + V"
V' = V - V"
(V - V")/V" = 5.55
V/V" - V"/V" = 5.55
V/V" - 1 = 5.55
V/V" = 5.55 + 1
V/V" = 6.55
V"/V = 1/6.55
V"/V = 0.153
So, the fish must inflate its air sacs to 0.153 of its expanded body volume
Answer:
This statement is true
Explanation:
The genetic code is required for the production of proteins with exception of some few mitochondrial proteins. The transfer RNA (tRNA) acts as an adaptor that enables to associate a messenger RNA trinucleotide sequence (known as anticodon) with its corresponding amino acid in the polypeptididic chain. The genetic code is considered to be a biochemical system capable of revealing the information contained in the DNA in order to synthetize a protein, which has been encrypted in the form of three nucleotides (i.e., codons).
Answer:
a. all purple flowers in the F1 generation.
Explanation:
According to the given information, the allele for purple flower color (lets assume P) is dominant over while the allele of flower color (p). When two pure breeding purple (PP) and white flowered (pp) plants are crossed, the F1 would have all "purple flowered progeny with genotype Pp".
According to the Mendel's law of dominance, the hybrid genotype exhibits the dominant phenotype. Here, the allele "P" is dominant over allele "p". Hence, the genotype "Pp" would exhibit purple flower color and all the F1 progeny would have purple flowers.
Answer:
hope this helps
Explanation:
White-tailed deer, mice, chipmunks, gray squirrels, opossums and raccoons can also be infected. How can my animal get Lyme disease? Lyme disease is spread through the bite of an infected tick. Wild mammals, especially small rodents and deer, can carry the bacteria in nature.
