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ch4aika [34]
3 years ago
7

you are ordering a meal and you have $15 to spend the the restaurant charges 6% sales tax you plan to leave a 15% tip the equati

on C equals X Plus 0.06x + 0.15x gives the total cost of c of your meal, where x is the cost before tax and tip. What is the maximum amount you can spend before tax and tip.
Mathematics
1 answer:
Rudik [331]3 years ago
5 0

C = x + 0.06x + 0.15x

15 = 1.21x

15/1.21 = x

12.40 = x

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3.- In a certain desert region the average number of persons who become seriously ill each year from eating a certain poisonous
Naily [24]

Answer:

P(X\geq 5)=1-P(X

Using the pmf we can find the individual probabilities like this:

P(X=0)=\frac{e^{-6.4} 6.4^0}{0!}=0.001662

P(X=1)=\frac{e^{-6.4} 6.4^1}{1!}=0.010634

P(X=2)=\frac{e^{-6.4} 6.4^2}{2!}=0.034029

P(X=3)=\frac{e^{-6.4} 6.4^3}{3!}=0.072595

P(X=4)=\frac{e^{-6.4} 6.4^4}{4!}=0.116151

And replacing we got:

P(X \geq 5) =0.76493

Step-by-step explanation:

Previous concepts

Let X the random variable that represent the number of people that will become sereiosly ill in two years. We know that X \sim Poisson(\lambda)

The probability mass function for the random variable is given by:

f(x)=\frac{e^{-\lambda} \lambda^x}{x!} , x=0,1,2,3,4,...

And f(x)=0 for other case.

For this case the value for \lambda would be:

\lambda = 3.2 \frac{ills}{year} *2 years = 6.4

For this distribution the expected value is the same parameter \lambda

E(X)=\mu =\lambda

On this case we are interested on the probability of having at least two chocolate chips, and using the complement rule we have this:

P(X\geq 5)=1-P(X

Using the pmf we can find the individual probabilities like this:

P(X=0)=\frac{e^{-6.4} 6.4^0}{0!}=0.001662

P(X=1)=\frac{e^{-6.4} 6.4^1}{1!}=0.010634

P(X=2)=\frac{e^{-6.4} 6.4^2}{2!}=0.034029

P(X=3)=\frac{e^{-6.4} 6.4^3}{3!}=0.072595

P(X=4)=\frac{e^{-6.4} 6.4^4}{4!}=0.116151

And replacing we got:

P(X \geq 5) =0.76493

7 0
3 years ago
Read 2 more answers
A radio disc jockey has
il63 [147K]

there will always be a 1/7 chance then 1/6 cause she's only doing one song. so, so sorry if I am wrong.


4 0
3 years ago
For each random variable defined here, describe the set of possible values for the variable, and state whether the variable is d
zavuch27 [327]

Answer:

The possible values for X is: {0,1,2,3,....,12}

Yes, it is a discrete random variable.

Step-by-step explanation:

Consider the provided information.

We need to determine whether the variable is discrete or not.

Discrete variables are which can only take on a finite number of values.

Let the variable X be the number of unbroken eggs in a randomly chosen standard egg carton.

In a standard egg carton we can put 12 eggs.

Therefore, the possible values for X is: {0,1,2,3,....,12}

The number of unbroken eggs (X) can take infinite values, thus by the above definition it is a discrete random variable.

3 0
3 years ago
HELP ASAP PLEASE you make $20 an hour and work fro 40 hours a week, you are paid biweekly and have $185 total deducted from your
VMariaS [17]

Answer:

615

Step-by-step explanation:u make $20 a week and u worked 40 hours u jus do 40*20=$800

800-185=615 im pretty sure hope this helps


8 0
3 years ago
Read 2 more answers
PLEASE HELP FOR 48 POINTS PLEASE!<br><br><br><br> show/explain your answer and work
pentagon [3]

Answer:

c  This is the direct variation

Step-by-step explanation:

The equation for direct variation is y= kx

Solving this for k

y/x =k

So y/x must be a constant

a.  9/3 =3

2/7 does not =3  so this is not a direct variation


b 1/2 = .5

-3/6 = -.5

This is not the same so this is not a direct variation


c.  27/9 =3

18/6 =3

9/3 =3

This is a direct variation with a constant of 3


d 5/-7 = -5/7

1/-3 = -1/3

This is not the same so this is not a direct variation

4 0
3 years ago
Read 2 more answers
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