Answer:
55.2° ...............................
Answer:
$149.66
Step-by-step explanation:
Step 1
Calculate Total Amount payable to the bank using compound interest
Total Amount payable (A) =
P(1 + r/n)^nt
P = Principal = $2000
r = Interest rate = 9% = 0.09
n = compounding interest = quarterly = 4
t = time in years = 2
Total Amount payable
= 2000(1 + 0.09/4)^0.09 × 2
A = $ 2,389.66
Interest = A - Principal
= $ 2,389.66 - $ 2,000.00
I (interest) = $ 389.66
Step 2
Calculate the Total amount payable to his uncle using simple interest.
Total Amount (A) = P(1 + rt)
P = Principal = $2000
r = Interest rate = 6% = 0.06
t = time in years = 2
A = 2000(1 + 0.06 × 2)
A = $2,240
A - Principal
= $ 2,240 - $ 2,000.
I (interest) = $240
Step 3
The amount of money you will save by borrowing the money from your uncle is calculated as:
Amount payable to the bank - Amount payable to your uncle
= $ 2,389.66 - $2,240
= $149.66
Therefore, the amount of money you will save by borrowing the money from your uncle is $149.66
Answer:
A.
Step-by-step explanation:
If
AND
y = x + 7, then by the transitive property of equality:

We can solve for the values of x by getting everything on one side of the equals sign and then solving for x:

We can factor out the common x to get:
x(x + 1) = 0
which tells us by the Zero Product Property that either
x = 0 and/or x + 1 = 0 and x = -1
We are expecting 2 solutions for x since this is a second degree polynomial. We will sub both -1 and 0 into y = x + 7 to solve for the corresponding values of y
y = 0 + 7 so
y = 7 and the coordinate is (0, 7)
y = -1 + 7 so
y = 6 and the coordinate is (-1, 6)
Where is the math u are talking about
Answer:

Step-by-step explanation:
Given that a shuttle launch depends on three key devices that may fail independently of each other with probabilities 0.01, 0.02, and 0.02, respectively.
Required probability = the probability for the shuttle to be launched on time
= Probability that all three do not fail
Since each key device is independent of the other
we have
prob that all three do not fail = 