Question

Find the equation of the line with slope m=−2 that contains the point (6,−15).

Answer 1

Answer:

$\boxed {y = -2x - 3}$

Step-by-step explanation:

Use the Point-Slope Formula to help you get your Slope-Intercept form:

$y - y_{1} = m (x - x_{1})$

(where $m$ represents the slope and $(x_{1}, y_{1})$ represents the second point)

-Apply the following slope and the first point:

Slope = $-2$

First Point = $(6, -15)$

$y + 15 = -2 (x - 6)$

-Solve:

$y + 15 = -2 (x - 6)$

$y + 15 = -2x + 12$

$y + 15 - 15 = -2x + 12 - 15$

$\boxed {y = -2x - 3}$

So, the slope-intercept is $y = -2x - 3$.

Answer 2

Answer:

y = -2x - 3

Step-by-step explanation:

y = mx + b

-15 = -2(6) + b

-15 = -12 + b

b = -3

y = -2x - 3