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Over [174]
3 years ago
6

What is the slope of the line that passes through the points (4, 8) and (-3, 1)?

Mathematics
1 answer:
blondinia [14]3 years ago
6 0

Answer:

1

Step-by-step explanation:

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Kevin has 32 golf balls. He puts the same number of golf balls into 8 bags. how many are in each bag
lozanna [386]

32 golf balls divided among 8 bags = 4 golf balls per bag

32 ÷ 8 = 4

<em>Hoped this helped!</em>

5 0
4 years ago
Read 2 more answers
Rewrite the sum of 30 and 42 by factoring out of the greatest common factor
kvasek [131]

Answer:

12

Step-by-step explanation:

Factors of 30: 1,2,3,5,(6),10,15,30

Factors of 42: 1,2,3,(6),7,14,21,42

30 divided by 6, 42 divided by 6

(5) + (7)= 12

8 0
3 years ago
In 1000 sq. meter of land a farmer cultivated 765 kg of rice with the wastage of 23.5%.I) Find the weight of the wastage. II) Fi
slega [8]

Answer:

i. weight of wastage(kg) = 179.775 kg

ii. weight of rice cultivated = 765 kg - 179. 775 kg = 585.225 kg

percentage of rice cultivated = 100 - 23.5 = 76.5%

Step-by-step explanation:

A land of 1000 sq. meter  is used to cultivate 765 kg of rice with wastage of 23.5%.

i. The wastage in percentage is 23.5% but the weight of the wastage in weight is  23.5% of 765 kg

weight of wastage = 23.5/100 × 765

weight of wastage = 17977.5/100

weight of wastage(kg) = 179.775 kg

ii. weight and percentage of rice cultivated.

weight of rice cultivated = 765 kg - 179. 775 kg = 585.225 kg

percentage of rice cultivated = 100 - 23.5 = 76.5%

8 0
3 years ago
A coin is tossed four times What is the probability of getting four heads? (1 mark) a) b) What is the probability of getting exa
BlackZzzverrR [31]
<h2>Answer:</h2>

1. A coin is tossed four times. What is the probability of getting four heads?

Each toss has a 1/2 chance of getting a head.

So the chance of getting all four heads can be calculated as :

1/2\times1/2\times1/2\times1/2=1/16

2. A coin is tossed four times. What is the probability of getting two heads?

Each toss can have 2 results, so 4 flips will have 2^{4} or 16 results.

Getting two heads means getting two tails also. So, we can get the number of times two heads come = \frac{4!}{2!2!} = 6

We can write the groups like - {HHTT,HTHT,HTTH,THHT,THTH,TTHH}

So, the required probability is : 6/16 or 3/8.

3. Not getting two heads means getting 3 tails and 1 head or all tails.

Probability of having all tails = 1/2\times1/2\times1/2\times1/2=1/16

Probability of one head(1st trial) and three tails = 1/16

Probability of one head (2nd trial) and three tails (the 1st, 3rd and 4th trials) = 1/16

Probability of one head (3rd trial) and three tails (the 1st, 2nd and 4th trials) = 1/16

Probability of one head (4th trial) and three tails (the 1st, 2nd and 3rd trials) = 1/16

So, the total probability showing only one or none head and at least three tails = 1/16+1/16+1/16+1/16+1/16=5/16

6 0
3 years ago
Perform the following division:
timofeeve [1]
(33/4) / (2/8)
when dividing with fractions, flip what u r dividing by, then multiply
33/4 * 8/2 = 66/2 = 33...hmm...not an answer choice

let me try something..
(3 3/4) / (2/8) =
15/4 * 8/2 =
30/2 =
15 <====possibly this one if ur problem is : (3 3/4) / (2/8)

5 0
3 years ago
Read 2 more answers
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