Solve: 2(x-2)=6 please! also calculate the area of a circle with a diametre of 6 if the pie= 3
1 answer:
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Answer:
There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.
Step-by-step explanation:
Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.
The problem reduces to take 11 consecutive spots which we will use to localize the balls and the sticks and select 3 places to put the sticks. The amount of ways to do this is As a result, we have 165 ways to distribute the blackboards.
If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is . Thus, there are only 35 ways to distribute the blackboards in this case.
Answer:
51.9 cm²
Step-by-step explanation:
From the diagram attached,
Area of the white region(segment)(A) = Area minor sector- area of the triangle
A = (πr²∅/360°)-(1/2r²sin∅)............... Equation 1
Where r = radius of the circle, Ф = reflex angle formed at the center of the circle, π = pie
From the question,
Given: r = 7 cm, Ф = 150°
Constant: π = 22/7
Substitute these values into equation 1
A = [(22/7)×7²×150/360]-[(1/2)×7²×sin150]
A = 64.17-12.25
A = 51.92
A = 51.9 cm²
