Question

If you are solving y 2+2y=48 by completing the square, the next line would be

Answer 1

For this case we have the following equation:

$y ^ 2 + 2y = 48$

By completing squares we have:

Step 1:

Add $(\frac {b} {2}) ^ 2$ on both sides:

$y ^ 2 + 2y + 1 = 48 + 1$

Step 2:

We rewrite the equation:

$(y + 1) ^ 2 = 49$

Step 3:

We solve the equation:

$y = \pm \sqrt {49} -1\\y = \pm7-1$

Solutions:

$y = 6\\y = -8$

Answer:

the next line would be:

$y ^ 2 + 2y + 1 = 48 + 1$

Answer 2

What number will make y^2 + 2y + __ a perfect square? Take coefficient of y, divide by 2, then square it = (2/2)^2 = 1 So add 1 to both sides, since y^2 + 2y + 1 = (y + 1)^2 y^2 + 2y + 1 = 49