Question

If a=15 and b=6, then 9a²-48ab+64b²=?​

Answer 1

Answer:

9

Step-by-step explanation:

Value of 'a' = 15

Value of 'b' = 6

Simplifying the expression given in question,

$9a^{2} -48ab+64b^{2}$

$=> (3a)^{2} - 2*3a*8b+(8b)^{2}$

$=>(3a-8b)^{2}$

Putting 'a' & 'b' in above expression ,

$(3a-8b)^{2} = (3*15-8*6)^{2} = (45-48)^{2} = (-3)^{2} =9$