All categories

3 years ago

Find the missing side length,when the area is 16 square units

Mathematics

1 answer:

rusak2 [61]3 years ago

3 0

A^2 = 16
a^2 = 4^2
a = 4

answer:<span> side length = 4 unit</span>

You might be interested in

What is the perimeter

lana [24]

The edges of it so 16 is the answer.

7 0

3 years ago

The decay rate for a radioactive isotope is 9.29.2 percent per year. find the half-life of the isotope. round to the nearest ten

Oxana [17]

Exponential decay is given by the equation

F = P(1 - r)^t

0.5 = 1(1 - 0.092)^t

0.5 = (0.908)^t

log 0.5 = log (0.908)^t

log 0.5 = t * log 0.908

t = (log 0.5)/(log 0.908)

t = 7.18

Answer: 7.2 years

4 0

3 years ago

The half-life of a radioactive substance is the time it takes for a quantity of the substance to decay to half of the initial am

posledela

Step-by-step walkthrough:

Well a standard half-life equation looks like this.

$N = N_0 * (\frac{1}{2})^{t/p$

$N_0$ is the starting amount of parent element.

$N$ is the end amount of parent element

$t$ is the time elapsed

$p$ is a half-life decay period

We know that the starting amount is 74g, and the period for a half-life is 2.8 days.

Therefore you can create a function based off of the original equation, just sub in the values you already know.

$N(t) = 74g * (\frac{1}{2})^{t/2.8days$

This is easy now that we have already made the function. Here we just reuse it, but plug in 2.8 days.

$N(t) = 74g * (\frac{1}{2})^{t/2.8days} = N(2.8days) = 74g * (\frac{1}{2})^{2.8days/2.8days}\\= 74g * \frac{1}{2} = 37g$

Now we just gotta do some algebra. Use the original function but this time, replace $N(t)$ with 10g and solve algebraically.

$10g = 74g * (\frac{1}{2})^{t/2.8days}\\\\\frac{10g}{74g} = (\frac{1}{2})^{t/2.8days}$

Take the log of both sides.

$log(\frac{5}{37}) = log((\frac{1}{2})^{t/2.8days})$

Use the exponent rule for log laws that, $log(b^x) = x*log(b)$

$log(\frac{5}{37}) = \frac{t}{2.8days} * log(\frac{1}{2})$

$\frac{log(\frac{5}{37})}{log(\frac{1}{2})} = \frac{t}{2.8days}$

$2.8 * \frac{log(\frac{5}{37})}{log(\frac{1}{2})} = t$

slap that in your calculator and you get

$t = 8.1 days$

7 0

2 years ago

Ayeeeeeeeeeee whats up

Ierofanga [76]

Answer:

not much

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

How many solutions does the nonlinear system of equations graphed below have?

anygoal [31]

Answer:

B. two

Step-by-step explanation:

4 0

2 years ago