Answer:
8th term of geometric sequence is 312500
Step-by-step explanation:
Given : 
and common ratio (r) = 5
We have to find the 8th term of the geometric sequence whose and common ratio (r) = 5
Geometric sequence is a sequence of numbers in which next term is found by multiplying by a constant called the common ratio (r).
......(1)
where 
is nth term and a is first term.
For given sequence
a can be find using and r = 5
Substitute in (1) , we get,
Thus, 8th term of the sequence denoted as 
Substitute n= 8 in (1) , we get,
Thus 8th term of geometric sequence is 312500
Subtract 10x
10x + y = -19
10x + 3y = -17
You would get:
-2y = -2
Two negatives make a positive number! Divide
y = 1
Plug in
10x + (1) = -19
10x = -20
Divide
x = -2
Your solutions are
x = -2
y = 1
Critical points is where the derivative (slope) is zero or does not exist. So to do this we have to find the derivative of our function:
So we apply chain rule:
=
Set our first derivative to zero and solve for x:
3(x^2 - 1) * 2x = 0
So we can see that (by plugging in) 0, -1 and 1 makes our solution true
So our critical value is x = 0, x = -1, x = 1
Answer:
Hey there!
We can solve this by multiplying 0.3 by 546, which is about 164.
Hope this helps :)
15% markup on $17,000 = 17000*.15=$2550
25% markup on $4,000 = 4000*.25 = $1000
now just add the two markups.
