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MA_775_DIABLO [31]
3 years ago
6

A textbook is opened and the product of the page numbers of the pages is 6162. What are the numbers of the pages?

Mathematics
1 answer:
ss7ja [257]3 years ago
6 0

Answer:

The two page numbers are 78 and 79.

Step-by-step explanation:

Let's take the page numbers are x and x + 1 .

The produce of the page numbers is 6162

so, x(x + 1) = 6162

x^{2} + x -6162 = 0

Here we have to use the quadratic formula to solve for x.

The quadratic formula, x = \frac{-b +/- \sqrt{b^2 - 4ac} }{2a}

Here a =1, b = 1 and c = -6162

Plugging in the value of a, b and c in the above formula, we get

x = [-1 ± 157] ÷ 2

Let's take the positive value alone since the page number cannot be negative.

x = [-1 + 157] ÷2

x = 78

The next page number x + 1 = 78 + 1 = 79

Therefore,  the two page numbers are 78 and 79.

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Without plotting points, let M=(-2,-1), N=(3,1), M'= (0,2), and N'=(5, 4). Without using the distanceformula, show that segments
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Given:

M=(x1, y1)=(-2,-1),

N=(x2, y2)=(3,1),

M'=(x3, y3)= (0,2),

N'=(x4, y4)=(5, 4).

We can prove MN and M'N' have the same length by proving that the points form the vertices of a parallelogram.

For a parallelogram, opposite sides are equal

If we prove that the quadrilateral MNN'M' forms a parallellogram, then MN and M'N' will be the oppposite sides. So, we can prove that MN=M'N'.

To prove MNN'M' is a parallelogram, we have to first prove that two pairs of opposite sides are parallel,

Slope of MN= Slope of M'N'.

Slope of MM'=NN'.

\begin{gathered} \text{Slope of MN=}\frac{y2-y1}{x2-x1} \\ =\frac{1-(-1)}{3-(-2)} \\ =\frac{2}{5} \\ \text{Slope of M'N'=}\frac{y4-y3}{x4-x3} \\ =\frac{4-2}{5-0} \\ =\frac{2}{5} \end{gathered}

Hence, slope of MN=Slope of M'N' and therefore, MN parallel to M'N'

\begin{gathered} \text{Slope of MM'=}\frac{y3-y1}{x3-x1} \\ =\frac{4-(-1)}{5-(-2)} \\ =\frac{3}{2} \\ \text{Slope of NN'=}\frac{y4-y2}{x4-x2} \\ =\frac{4-1}{5-3} \\ =\frac{3}{2} \end{gathered}

Hence, slope of MM'=Slope of NN' nd therefore, MM' parallel to NN'.

Since both pairs of opposite sides of MNN'M' are parallel, MM'N'N is a parallelogram.

Since the opposite sides are of equal length in a parallelogram, it is proved that segments MN and M'N' have the same length.

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