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3 years ago

Help me please !!!!!

Mathematics

1 answer:

Serga [27]3 years ago

4 0

Answer:

6. B

7. A

8. B

Step-by-step explanation:

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A scale on a map shows that 2 inches = 25 miles

ycow [4]

4.4 inches because once you add 2 and 2 you 50 then add ten and you get 60

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3 years ago

Emily took 300 US dollars to the bank to exchange it for Canadian dollars. The exchange rate on that day was 1.25 Canadian dolla

Paha777 [63]

Emily wanted to exchange her 300 US Dollars for Canadian Dollars.

The exchange rate for it was 1.25 Canadian Dollars for 1 US Dollar.

This means that 1 US Dollar = 1.25 Canadian Dollars.

So if we were to follow this pattern,

2 US Dollars = 2 × 1.25 = 2.5 Canadian Dollars

3 US Dollars = 3 × 1.25 = 3.75 Canadian Dollars

4 US Dollars = 4 × 1.25 = 5 Canadian Dollars

So for 300 US Dollars, we'll need to multiply 300 by 1.25.

300 US Dollars = 300 × 1.25 = 375 Canadian Dollars.

Hope it helps. :)

4 0

3 years ago

Jim drove 204 miles in 4 hours. If he can keep the same pace how long will it take him to drive 918 miles

SSSSS [86.1K]

18 hours.

Proportions and stuff.

$\frac{204}{4}$ = $\frac{918}{x}$

Cross multiply,

204x = 918 * 4

204x = 3672
/204 /204
x = 18

18 hours.

6 0

3 years ago

1+secA/sec A = sin^2 A / 1-cos A

Fofino [41]

Answer: see proof below

<u>Step-by-step explanation:</u>

$\dfrac{1+\sec A}{\sec A}=\dfrac{\sin^2 A}{1-\cos A}$

Use the following Identities:

sec Ф = 1/cos Ф

cos² Ф + sin² Ф = 1

<u>Proof LHS → RHS</u>

$\text{LHS:}\qquad \qquad \dfrac{1+\sec A}{\sec A}$

$\text{Identity:}\qquad \qquad \dfrac{1+\frac{1}{\cos A}}{\frac{1}{\cos A}}$

$\text{Simplify:}\qquad \qquad \dfrac{\frac{\cos A+1}{\cos A}}{\frac{1}{\cos A}}\\\\\\.\qquad \qquad \qquad =\dfrac{1+\cos A}{1}$

$\text{Multiply:}\qquad \qquad \dfrac{1+\cos A}{1}\cdot \bigg(\dfrac{1-\cos A}{1-\cos A}\bigg)\\\\\\.\qquad \qquad \qquad =\dfrac{1-\cos^2 A}{1-\cos A}$

$\text{Identity:}\qquad \qquad \dfrac{\sin^2 A}{1-\cos A}$

$\text{LHS = RHS:}\quad \dfrac{\sin^2 A}{1-\cos A}=\dfrac{\sin^2 A}{1-\cos A}\quad \checkmark$

3 0

3 years ago

Can someone help me answer this?

Masja [62]

Your answer is angle JCL.

Angle JCL+Angle LCT = 90°

3 0

3 years ago

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