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1 answer:
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Answer:
a)The 98% of confidence intervals are
Lower bound of CI = 47 -3.82436 = 43.1756
Upper bound of CI = 47 + 3.82436 = 50.8243
b) The conditions are required for the validity of the interval
A) μ known
Step-by-step explanation:
<u>Explanation</u>:-
The given sample size is 'n' =11
Given the average number of seeds is 47 with a standard deviation of 7
Sample mean (x⁻) = 47
Standard deviation (S) = 7
<u>The 98% of confidence intervals are</u>
The degrees of freedom = n-1 =11-1 =10
t₀.₀₂= 1.812 ( from t - table)
now the intervals are
<u>Lower bound of CI = 47 -3.82436 = 43.1756</u>
<u>Upper bound of CI = 47 + 3.82436 = 50.8243</u>
The conditions are required for the validity of the interval
<u>A) μ known</u>
<u>Explanation</u>:-
If a random sample xi of size 'n' has been drawn from a normal population with a specified mean (μ) known.
The limit for (μ) is given by
Answer:
a = -10
Step-by-step explanation:
solving inequation : a -6.5 so a = -10 complies