Y=v(initial)*t+1/2at^2
since the velocity is zero at the maximum height then we get
y=1/2at^2
a is just acceleration due to gravity so a=g which is 9.8 m/s^2.
so y=1/2gt^2.
In triangle ACE,
we know C=93,E can be calulated by using arch angle AEC...what ever that is....,using this we get A=180-(E+93)
So, by alternate segment theorem, DCE= A.
thats all i can say.
Answer:
The correct answer is actually B. x - 3y < 5
Step-by-step explanation:
Because you must convert the equation to y-intercept form first.
Which makes it y = 1/3x - 1.6
So y = 1.6 and using the slope of 1/3x you can find that x = 5
Answer:
we have the expression as;
1/sin u cos u
Step-by-step explanation:
tan u = sin u/cos u
cot u = cos u/sin u
Thus;
sin u/cos u + cos u/sin u
The lcm is sin u cos u
Thus, we have that;
(sin^2 u + cos^2 u)/sin u cos u
But ; sin^2 u + cos^2 u = 1
so we have ;
1/sin u cos u
