Which quantity is larger?

2 answers:

8 0

Remember
$(x^m)^n=x^{mn}$
convert to base 10
$100^{500}=(10^2)^{500}=10^{1000}$
$1000^{300}=(10^3)^{300}=10^{900}$

$10^{1000}\ \textgreater \ 10^{900}$

A is larger

xenn [34]3 years ago

6 0

100^500 = (10^2)^500 = 10^(2*500) = 10^1000
1000^300 = (10^3)^300 = 10^(3*300) = 10^900
therefore, 100^500 is greater than 1000^300

answer is letter A

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Solve the inequality.

maw [93]

The solution to inequality is less than the negative of 21. Then the correct option is C.

<h3>What is inequality?</h3>

Inequality is defined as an equation that does not contain an equal sign. Inequality is a term that describes a statement's relative size and can be used to compare these two claims.

The inequality is given below.

−(1/3)x + 10 > 17

Then the solution to the inequality will be

−(1/3)x + 10 > 17

−(1/3)x > 17− 10

−(1/3)x > 7

When the sign is changed then the equality sign also changed.

(1/3)x < −7

x < − 21

The value of x is less than the negative of 21.

Thus, the correct option is C.

More about the inequality link is given below.