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lyudmila [28]
3 years ago
11

If BC = 6 and AD = 5, find DC.

Mathematics
1 answer:
bekas [8.4K]3 years ago
3 0
The answer is 4. You should’ve posted a picture
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Tell which value of the variable is the solution of the equation. 6c=96; c=14,15,16,17
otez555 [7]

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c = 16

Explanation:

Do it on a calculator it'll be correct

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30 people liked Brand X. This is 20% of the people in a survey.
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A) 150 people
b) 80%
c) 120 people
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Is there a graph for this question?
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5. Is the number 0.6 with the line on top rational or irrational?
mafiozo [28]

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Step-by-step explanation:

8 0
3 years ago
A research firm needs to estimate within 3% the proportion of junior executives leaving large manufacturing companies within thr
Y_Kistochka [10]

Answer:

972 junior executives should be surveyed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

35% of junior executives left their company within three years.

This means that \pi = 0.35

0.95 = 95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

To update this study, how many junior executives should be surveyed?

Within 3% of the proportion, which means that this is n for which M = 0.03. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.35*0.65}{n}}

0.03\sqrt{n} = 1.96\sqrt{0.35*0.65}

\sqrt{n} = \frac{1.96\sqrt{0.35*0.65}}{0.03}

(\sqrt{n})^2 = (\frac{1.96\sqrt{0.35*0.65}}{0.03})^2

n = 971.2

Rounding up:

972 junior executives should be surveyed.

5 0
3 years ago
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