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3 years ago

If BC = 6 and AD = 5, find DC.

Mathematics

1 answer:

bekas [8.4K]3 years ago

3 0

The answer is 4. You should’ve posted a picture

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What two ratios are equivalent to 10:18

Whitepunk [10]

10 : 18 2 into 10 is 5, 2 into 18 is 9.

5 : 9.

You can also choose to multiply 10 : 18 by 2.

2*10 : 2*18

20 : 36.

Therefore 5 : 9 and 20 : 36 are two ratios that are equivalent to 10 : 18.

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4 years ago

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3 years ago

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We are going to fence in a rectangular field. If we look at the field from above the cost of the vertical sides are $10/f t, the

Brut [27]

Answer:

Dimensions are 350/9 ft and 17.5 ft

Step-by-step explanation:

We are given the cost per ft of all the 4 sides. Let the horizontal be x and the vertical be y.

Now, we will set up the constraint and equation that we are being asked to maximize.

Thus;

700 = 10y + 10y + 7x + 2x

700 = 20y + 9x

Maiking y the subject, we have;

y = (700 - 9x)/20

y = 35 - 9x/20

Now,area of a rectangle is: A = xy

Thus, A = x(35 - 9x/20))

A = 35x - 9x²/20

We can get the critical points by finding the derivatives and Equating to zero

Thus;

dA/dx = 35 - 0.9x

At dA/dx = 0,we have; x = 350/9

At d²A/dx², we have;

d²A/dx² = -0.9

This is negative, thus we will disregard and use the one gotten from the first derivative.

Thus, we will use x = 350/9 ft

Plugging this into the equation y = 35 - 9x/20, we have;

y = 35 - ((9 × 350/9)/20)

y = 17.5 ft

7 0

4 years ago

ASAP!!! ILL GIVE BRAINLIEST

Ostrovityanka [42]

Answer:

The correct options are 2 and 4.

Step-by-step explanation:

From the given box plot it is clear that

$\text{Minimum value}=20$

$Q_1=25$

$Median=40$

$Q_3=50$

$\text{Maximum value}=110$

We know that these number divides the data in four equal parts.

$Q_1=25\%$

$Median=50%$

$Q_3=75\%$

25% of the data values lies between 50 and 110. Therefore option 1 is incorrect.

Seventy-five percent of the data values lies between 20 and 50. Therefore option 2 is correct.

It is unlikely that there are any outliers. This statement is not true because the is a huge difference between third quartile and maximum value.

Therefore option 3 is incorrect.

The interquartile range is

$IQR=Q_3-Q_1=50-25=25$

Therefore option 4 is correct.

The range is

Range = Maximum-Minimum

$Range=110-20=90$

Therefore option 5 is incorrect.

4 0

3 years ago

D/5 = 4 please explain I do not get this. Thank you

MAXImum [283]

<span>D/5 = 4
Multiply 5 on both sides
Final Answer: D = 20</span>

8 0

3 years ago