Answer:
sinP = 7/25
cosQ = 7/25
tanP = 7/24
cotQ = 7/24
secP = 25/7
cscQ = 25/24
Step-by-step explanation:
<em>sin∅</em> is opposite over hypotenuse
<em>cos∅</em> is adjacent over hypotenuse
<em>tan∅</em> is opposite over adjacent or sin∅/cos∅
<em>csc∅</em> is hypotenuse over opposite or 1/sin∅
<em>sec∅</em> is hypotenuse over adjacent or 1/cos∅
<em>cot∅</em> is adjacent over opposite or cos∅/sin∅
Since triangle RQP is a right triangle, we can use trig and Pythagorean Theorem: a² + b² = c²
The missing side length RQ after we use Pythagorean Theorem would be 7.
From there, we can find the trigonometric values.
