Answer:
2
Step-by-step explanation:
( n^2)×3 can be written as 3(n^2)
Answer:
C. (-1, 3)
Step-by-step explanation:
Label the 2 equations:
5y= 7x +22 -----(1)
x= -6y +17 -----(2)
Substitute (2) into (1):
5y= 7(-6y +17) +22
5y= -42y +119 +22 <em>(</em><em>Expand</em><em> </em><em>bracket</em><em>)</em>
5y= -42y +141 <em>(</em><em>Simplify</em><em>)</em>
42y +5y= 141 <em>(</em><em>+</em><em>42y</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>
47y= 141
y= 141 ÷47 <em>(</em><em>÷</em><em>4</em><em>7</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>
y= 3
Substitute y= 3 into (2):
x= -6(3) +17
x= -18 +17
x= -1
Thus, the solution is (-1, 3).
Answer:
(9-27)+9
=-18+9
<em><u>=-9</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>answer</u></em>
Answer:
Never
Never
Never
Step-by-step explanation:
The equations given are
2x1−6x2−4x3 = 6 ....... (1)
−x1+ax2+4x3 = −1 ........(2)
2x1−5x2−2x3 = 9 ..........(3)
the values of a for which the system of linear equations has no solutions
Let first add equation 1 and 2. Also equation 2 and 3. This will result to
X1 + (a X2 - 6X2) - 0 = 5
And
X1 + (aX2-5X2) + 2X3 = 8
Since X2 and X3 can't be cancelled out, we conclude that the value of a is never.
a unique solution,
Let first add equation 1 and 2. Also equation 2 and 3. This will result to
X1 + (a X2 - 6X2) - 0 = 5
And
X1 + (aX2-5X2) + 2X3 = 8
The value of a = never
infinitely many solutions.
Divide equation 1 by 2 we will get
X1 - 3X2 - 2X3 =3
Add the above equation with equation 3. This will result to
3X1 - 8X2 - 4X3 = 12
Everything ought to be the same. Since they're not.
Value of a = never.
Answer:
3,114 in 240 days
Step-by-step explanation:
3000 x 0.038=114
114+3000=3114