You know vertical Angles SRU and TRV are congruent.
You are given that Sides UR and VR are congruent.
You are given that Angles SUT and SVT are congruent.
An appropriate choice is the ASA postulate, since you have congruent angles with congruent sides in between.
Answer:
Where's the problem?
Step-by-step explanation:
Answer:
This (x - 5) represents the length of the rectangle.
Step-by-step explanation:
The formula for the area of a rectangle of length L and width W is A = L * W.
Here, the width is x - 4 and the area is x^2 + x - 20. Dividing the width (x - 4) into the area results in an expression for the length:
x - 4 / x^2 + x - 20
Let's use synthetic division here. It's a little faster than long division.
If the divisor in long division is x - 4, we know immediately that the divisor in synthetic division is 4:
4 / 1 1 -20
4 20
--------------------
1 5 0
This synthetic division results in a remainder of 0. This tells us that 4 (or the corresponding (x - 4) is indeed a root of the polynomial x^2 + x - 20, and so *(x - 4) is a factor. From the coefficients 1 and 5 we can construct the other factor: (x - 5). This (x - 5) represents the length of the rectangle.
Answer:
1f 2×4 -3׳ 12k is divided by × - 3 the remainder is 21 find the value of k
2 1/2 is also 2.5, therefore to calculate each liter, just 60/2.5, so the answer is $24
