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2 years ago

Question 16

Mathematics

1 answer:

Nina [5.8K]2 years ago

6 0

The answer is 1.78 but rounded to the nearest tenth would be 1.8 which would be A.
hope this helps!

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Multiply the polynomials.<br> (4x- + 4x + 6)(7x + 5)

SashulF [63]

$\implies {\blue {\boxed {\boxed {\purple {\sf { \: 28 {x}^{3} + 48 {x}^{2} + 62x + 30}}}}}}$

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}$

$(4 {x}^{2} + 4x + 6)(7x + 5)$

$= \: 7x(4 {x}^{2} + 4x + 6) + 5(4 {x}^{2} + 4x + 6)$

$= \: 28 {x}^{3} + 28 {x}^{2} + 42x + 20 {x}^{2} + 20x + 30$

Combining like terms, we have

$= \: 28 {x}^{3} + (28 {x}^{2} + 20 {x}^{2} ) + (42x + 20x) + 30$

$= \: 28 {x}^{3} + 48 {x}^{2} + 62x + 30$

$\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}$

3 0

3 years ago

Substitution again help please

Vesnalui [34]

Answer:

Step-by-step explanation:

1) 4x -3

x = -7 ;

4x - 3 = 4*(-7) - 3 = - 28 - 3 = -31

x = 14 ;

4x - 3 = 4*14 - 3 = 56 - 3 = 53

x = 0

4x - 3 = 0 - 3 = -3

2) 6 -3x

x = -7 ;

6 - 3x = 6 - 3*(-7) = 6 + 21 = 27

x = 14

6 - 3x = 6 - 3*14 = 6 - 42 = -36

x = 0

6 - 3x = 6 - 0 = 6

$3) \dfrac{3x - 21}{7}\\\\x = -7\\\\\\\dfrac{3*(-7)-21}{7}=\dfrac{-21-21}{7}=\dfrac{-42}{7}=-6\\\\\\x = 14\\\\\dfrac{3*14-21}{7}=\dfrac{42-21}{7}=\dfrac{21}{7}=3\\\\\\x=0\\\\\dfrac{0-21}{7}=\dfrac{-21}{7}=-3\\\\$

$\dfrac{3x}{7}-21\\\\\\x = -7\\\\\dfrac{3*(-7)}{7}-21=-3-21=-24\\\\\\x =14\\\\\dfrac{3*14}{7}-21=3*2-21=6-21=-15\\\\\\x=0\\\\\dfrac{0}{7}-21=-21$

8 0

2 years ago

Determine if (-2,6) and (4,12) are solutions to the system of equations:

kykrilka [37]

Answer:

Both $(-2,6)$ and $(4,12)$ are solutions to the system.

Step-by-step explanation:

In order to determine whether the two given points represent solutions to our system of equations, we must "plug" thos points into both equations and check that the equality remains valid.

Step 1: Plug $(-2,6)$ into $y=x+8$