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3 years ago

Is 5p+5c equal to 5(p+c)

Mathematics

2 answers:

melisa1 [442]3 years ago

8 0

When using distributive properties yes.

Nadya [2.5K]3 years ago

4 0

Yes, this is true. When using the distributive property, you do the number times the letters/numbers inside and do the operation that was inside the parenthesis. So, you do 5 times p and 5 times c. The operation inside the parenthesis what addition, so you add the two products. The new equation would be 5p+5c. So, as an inequality, 5p+5c=5(p+c).

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Minchanka [31]

Answer:

15 students

Step-by-step explanation:

from the algebra = 24 - 10 = 14

from the draft = 11 - 10 = 1

14 + 1 = 15

the total students that are taking algebra or drafting but not both is 15 students

4 0

3 years ago

Read 2 more answers

What is the square root of 5 divided by the square root of 15 and simplify and in fraction form

ozzi

Answer:

$\sqrt{\frac{1}{3} }$

$\frac{\sqrt{3} }{3}$

Step-by-step explanation:

The expression $\frac{\sqrt{5} }{\sqrt{15} }$ can be simplified by first writing the fraction under one single radical instead of two.

$\frac{\sqrt{5} }{\sqrt{15} } = \sqrt{\frac{5}{15} }$

5/15 simplifies because both share the same factor 5.

It becomes $\sqrt{\frac{5}{15} } = \sqrt{\frac{1}{3} }$

This can simplify further by breaking apart the radical.

$\sqrt{\frac{1}{3} } = \frac{\sqrt{1} }{\sqrt{3} } = \frac{1}{\sqrt{3} }$

A radical cannot be left in the denominator, so rationalize it by multiplying by √3 to numerator and denominator.

$\frac{1}{\sqrt{3} } *\frac{\sqrt{3} }{\sqrt{3} } =\frac{\sqrt{3} }{3}$

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3 years ago

Flying with the wind, a small plane flew 404 mi in 2 h. Flying against the wind, the plane could fly only 386 mi in the same amo

Alika [10]

Answer: rate of the plane is 197.5 mph

rate of wind is 4.5 mph

Step-by-step explanation:

Let x represent the rate of the plane in calm air.

Let y represent the rate of the wind.

Flying with the wind, a small plane flew 404 mi in 2 h. This means that the total speed with which the plane flew is (x + y) mph.

Distance = speed × time

Distance travelled by the plane while flying with the wind is

404 = 2(x + y)

Dividing both sides of the equation by 2, it becomes

202 = x + y- - - - - - - - - - - 1

Flying against the wind, the plane could fly only 386 mi in the same amount of time. This means that the total speed at which the plane flew is (x - y) mph.

Distance = speed × time

Distance travelled by the plane while flying against the wind is

386 = 2(x - y)

Dividing both sides of the equation by 2, it becomes

193 = x - y- - - - - - - - - - - 2

Adding equation 1 to equation 2, it becomes

395 = 2x

x = 395/2

x = 197.5

Substituting x = 197.5 into equation 1, it becomes

202 = 197.5 + y

y = 202 - 197.5

y = 4.5

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