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wolverine [178]
4 years ago
15

Solve three-halvesx – 4 = 16

Mathematics
1 answer:
Leto [7]4 years ago
4 0
3/2x - 4 = 16

Add 4 to both sides.

3/2x = 20

Multiply by 2/3.

x = 13 1/3
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6 0
3 years ago
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(2a+b)^2 how do you do this
gulaghasi [49]

•  Expand (2a + b)²:

(2a + b)²

= (2a + b) · (2a + b)


Multiply out the brackets by applying the distributive property of multiplication:

= (2a + b) · 2a + (2a + b) · b

= 2a · 2a + b · 2a + 2a · b + b · b

= 2²a² + 2ab + 2ab + b²


Now, group like terms together, and you get

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= 4a² + 4ab + b²    <———    expanded form  (this is the answer).


I hope this helps. =)


Tags:  <em>special product square of a sum algebra</em>

3 0
3 years ago
Square root of -49 in terms of i
natita [175]

Answer:

7i

Step-by-step explanation:

We know that  i = √-1

Then solving the given:

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So the answer is:

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3 0
3 years ago
Given: // CDAB , ∠≅∠ DB and ≅ EDBF . Prove: Δ ABF ≅ Δ CED
SCORPION-xisa [38]

Given: line segment AB // to line segment CD, ∠B ≅∠D and line segment BF ≅ to line segment ED. Prove: Δ ABF ≅ Δ CED.

Follow the matching numbers on the statement versus reason chart.

Statement:

1. line segment AB // to line segment CD.

2. ∠B ≅∠D

3. line segment BF ≅ to line segment ED.

4. ∠A ≅∠C

5. Δ ABF ≅ Δ CED

 

Reason:

1. Given

2. Given

3. Given

4. Alternate interior angles are congruent.

5. Corresponding parts of congruent triangles are congruent.

4 0
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