Answer:
156in squared
Step-by-step explanation:
Answer:
In a system, the substitution method is one of the 3 main ways to solve a system and can be very efficient at times.
<u>Skills needed: Systems, Algebra</u>
Step-by-step explanation:
1) Let's say we are given two equations below:

We can use substitution here by substituting in for
in the second equation. This means we put in
for
in the 2nd equation so we only have
variables in the equation, allowing us to solve for
.
2) Solving it out:

We essentially substitute in that value as seen in step 1. Steps 2 and 3 are just simplifying the left side and allowing for us to solve. Step 4 is where we divide by -16 on both sides to solve for x. Step 5 and 6 show us solving for y using the value for x. We get 
Answer:
a. the product of 11 and x
b. 9 greater than x
c. x less than 18
d. the product of 4 and the difference of x and 3
Step-by-step explanation:
Answer:
the answer is d.
Step-by-step explanation:
first, you want to use the formula,
new value - original value
<u>____________________</u>
original value * 100
you see that 84 is the new value and 79 would be the original value. substitute the numbers in. this is a increase since you will get a positive value.
84 - 79
<u>______</u>
79 * 100
now we solve it.
5
<u>__</u>
79 * 100
you can either solve the fraction first then multiply that by 100 or multiply the numerator by 100 first then divide that by 79, each way works.
500
<u>____</u>
79 = approximately 6.3% increase (this is not a exact value, just rounded)
or
5
<u>__</u>
79 = approximately 0.063 (this is not a exact value, just rounded)
0.063 * 100 = 6.3% increase
Answer:
y=120
Step-by-step explanation:
Y varies directly as x is written as

introducing a constant
y=kx
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<em>sub</em><em>stitute</em><em> </em><em>it</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>form</em><em>ula</em>
<em>4</em><em>8</em><em>=</em><em>6</em><em>k</em>
<em>making</em><em> </em><em>k</em><em> </em><em>the</em><em> subject</em><em> </em><em>by </em><em>divi</em><em>ding</em><em> </em><em>thr</em><em>ough</em><em> </em><em>by</em><em> </em><em>6</em>
<em>
</em>
k=48/6
k=8
<em>put</em><em> </em><em>the</em><em> </em><em>va</em><em>lue</em><em> </em><em>of</em><em> </em><em>k</em><em> </em><em>in</em><em> </em><em>the </em><em>expression</em><em> </em><em>y</em><em>=</em><em>kx</em>
<em>y</em><em>=</em><em>8</em><em>x</em>
from the question,the value of y when x=15 is given by
y=8×15
y=120.