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Natalija [7]
3 years ago
11

Question is: use words to describe each algebraic expression

Mathematics
2 answers:
BigorU [14]3 years ago
7 0
<h2>Answer with explanation:</h2>

We are asked to express each of the given four algebraic expression as a word phrase i.e. we have to use words to describe each algebraic expression.

1)

           6c

The product of 6 and c.

2)

         X-1

1 is subtracted from X.

3)

            T over 2 i.e. T/2

T is divided by 2.

4)

            3t-4

The number 4 is subtracted from the product of 3 and t.

   

tekilochka [14]3 years ago
3 0
1. six times c/ six c times/ six c
2. x minus one/ x subtract one
3. T divided by two/ T over two
4. three t minus four/ three times t minus four/ the product of t and three minus/subtracted (by) 4
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2. A bakery makes muffins and cookies. Muffins are sold 18 to a box and cookies are sold 25 to a bag. They do not sell individua
Ksivusya [100]
A) if 18 muffins = 1 box,
1020 muffins = 1020/18 boxes
= 56.67 boxes

So they used 56 full boxes.

b) if 25 cookies = 1 bag
2820 cookies = 2820/25 bags
= 112.8 bags

So they used 112 full bags.

c) the remainders from a and b represent muffins and cookies left over.
8 0
2 years ago
Three water storage containers have the same volume in the shape of a cylinder, a cone, and a sphere. The base radius of the cyl
fredd [130]

Answer:

- The ratio of the height of the cone to the height of the cylinder is 3:1

- The ratio of the height of the cone to radius of the sphere is 4:1

Step-by-step explanation:

Note that the radii of all the structures are the same.

Let the height of the cone be H and the height of the cylinder be h

The volume of each of the shapes are given below as

Volume of cylinder = πr²h

Volume of a cone = (1/3)πr²H

Volume of a sphere = (4/3)πr³

1) The ratio of the height of the cone to the height of the cylinder

To obtain this, we equate the volume of those two structures

Volume of the cone = Volume of the cylinder

(1/3)πr²H = πr²h

πr² cancels out on both sides and we're left with

(H/3) = h

H = 3h

(H/h) = (3/1)

So, The ratio of the height of the cone to the height of the cylinder is 3:1

2) The ratio of the height of the cone to radius of the sphere

Similarly equating the volumes of the cone and the sphere

(1/3)πr²H = (4/3)πr³

(1/3)πr² cancels out on both sides and we're left with

H = 4r

(H/r) = (4/1)

The ratio of the height of the cone to radius of the sphere is 4:1

Hope this Helps!!!

8 0
3 years ago
Simplify the expression show all your work 18 / 2 x 3 over 5 - 2
11Alexandr11 [23.1K]

Answer:

18÷2 × 3 / 5-2

9 ×3 / 3

27/3

9

tyvm this was my 100th answer :)

6 0
3 years ago
In a movie theater, there are children and adults in the ratio 4:7. If there are 21 adults, how many people total are there in t
lozanna [386]

Answer:

33

Step-by-step explanation:

7x3=21

4x3=12

21+12=33

8 0
3 years ago
How much of a radioactive kind of thorium will be left after 14,680 years if you start with
babymother [125]

Answer:

8978 grams

Step-by-step explanation:

The equation to find the half-life is:

N(t)= N_{0}e^{-kt}

N(t) = amount after the time <em>t</em>

N_{0} = initial amount of substance

t = time

It is known that after a half-life there will be twice less of a substance than what it intially was. So, we can get a simplified equation that looks like this, in terms of half-lives.

N(t)= N_{0}e^{-\frac{ln(\frac{1}{2}) }{t_{h} } t} or more simply N(t)= N_{0}(\frac{1}{2})^{\frac{1}{t_{h} } }

t_{h} = time of the half-life

We know that N_{0} = 35,912, t = 14,680, and t_{h}=7,340

Plug these into the equation:

N(t) = 35912(\frac{1}{2})^{\frac{14680}{7340} }

Using a calculator we get:

N(t) = 8978

Therefore, after 14,680 years 8,978 grams of thorium will be left.

Hope this helps!! Ask questions if you need!!

8 0
2 years ago
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