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Natasha2012 [34]
3 years ago
14

State the half-angle identities used to integrate sin^(2) x and cos^(2) x

Mathematics
1 answer:
ikadub [295]3 years ago
4 0

Answer:

the answer is D

Step-by-step explanation:

Think of the Pythagorean Theorem which states that a^2 + b^2 = c^2. The Pythagorean Identities used in trigonometry are the angle version which can be used to simplify expressions.  

HOPE THIS HELPED ;3

 

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144 coins are divided equally among some
nalin [4]

Answer:

Consider the number of children to be x.

So, 144 coins were divided amongst x children.

For x-3 children, each child would have 16 coins

So, (x-3)*16=144

Solving for x, x-3=144/16

or x-3=9

or x=9+3=12

Answer is 12

3 0
3 years ago
Read 2 more answers
9.4 The heights of a random sample of 50 college stu- dents showed a mean of 174.5 centimeters and a stan- dard deviation of 6.9
gladu [14]

Answer:  a) (176.76,172.24), b) 0.976.

Step-by-step explanation:

Since we have given that

Mean height  = 174.5 cm

Standard deviation = 6.9 cm

n = 50

we need to find the 98% confidence interval.

So, z = 2.326

(a) Construct a 98% confidence interval for the mean height of all college students.

x\pm z\times \dfrac{\sigma}{\sqrt{n}}\\\\=(174.5\pm 2.326\times \dfrac{6.9}{\sqrt{50}})\\\\=(174.5+2.26,174.5-2.26)\\\\=(176.76,172.24)

(b) What can we assert with 98% confidence about the possible size of our error if we estimate the mean height of all college students to be 174.5 centime- ters?

Error would be

\dfrac{\sigma}{\sqrt{n}}\\\\=\dfrac{6.9}{\sqrt{50}}\\\\=0.976

Hence, a) (176.76,172.24), b) 0.976.

8 0
3 years ago
Nadia has a $15 gift card to an online music store. Each song at the store costs $0.99. The equation m = 15 - 0.99s represents t
ololo11 [35]

Answer:

All I know is she had 10.05 left

5 0
2 years ago
Can you guys please help!
yuradex [85]

Answer:

5 for the first and 4x for the second one also plz give heart

Step-by-step explanation:

i just know

4 0
3 years ago
Lucy is using a one-sample t ‑test based on a simple random sample of size n = 22 to test the null hypothesis H 0 : μ = 16.000 c
slega [8]

Answer:

The value of test statistic is 1.338

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 16.000

Sample mean, \bar{x} = 16.218

Sample size, n = 22

Alpha, α = 0.05

Sample standard deviation, s = 0.764

First, we design the null and the alternate hypothesis

H_{0}: \mu = 16.000\text{ cm}\\H_A: \mu < 16.000\text{ cm}

We use one-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{16.218 - 16.000}{\frac{0.764}{\sqrt{22}} } = 1.338

Thus, the value of test statistic is 1.338

4 0
3 years ago
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