

- <u>We </u><u>have </u><u>given </u><u>that </u><u>the </u><u>coordinates </u><u>of </u><u>the </u><u>end </u><u>point </u><u>G </u><u>and </u><u>H </u><u>are </u><u>(</u><u> </u><u>-</u><u>6</u><u>,</u><u>5</u><u>)</u><u> </u><u>and </u><u>(</u><u> </u><u>2</u><u>,</u><u> </u><u>-</u><u>7</u><u> </u><u>)</u>

- <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>length </u><u>of </u><u>GH </u>

The coordinates of G = ( -6 , 5 )
The coordinates of H = ( 2 , - 7 )
<u>According </u><u>to </u><u>the </u><u>distance </u><u>formula</u><u>, </u><u> </u><u>we </u><u>get </u><u>:</u><u>-</u><u> </u>

- <u>Here</u><u>, </u><u> </u><u>x1</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>,</u><u> </u><u>x2</u><u> </u><u>=</u><u> </u><u>2</u><u> </u><u>and </u><u>y1</u><u> </u><u>=</u><u> </u><u>5</u><u> </u><u>,</u><u> </u><u>y2</u><u> </u><u>=</u><u> </u><u>-</u><u>7</u>
<u>Subsitute </u><u>the </u><u>required </u><u>values </u><u>in </u><u>the </u><u>above </u><u>formula </u>








Angle two would be 180-m<1
180-52= 128
Measurement of angle two is 128 degrees
Answer:
Nori would have 9/12 of a bag left.
Step-by-step explanation:
she had 2 2/12 and she used 1 5/12 so you subtract them and get 9/12
Answer:
301.224 g
Step-by-step explanation:
Let's divide in the ratio 21:4 the volume of the medal (35cm^3)
copper = (21/25)(35cm^3) = 29.4cm^3
tin = (35 - 29.4)cm^3 = 5.6cm^3
<em>FOR THE COPPER</em>
8.84 : 1 = X : 29.4
X = 259.896(g)
<em>FOR THE TIN</em>
7.38 : 1 = X : 5.6
X = 41.328(g)
<em>(259.896 + 41.328)g </em><em>=</em><em> 301.224 g</em>