Let's move like a crab, backwards some.
after 2 years?

after 3 years?

is that enough to pay the $1100?
now, let's write 1000(1+r)² in standard form
1000( 1² + 2r + r²)
1000(1 + 2r + r²)
1000 + 2000r + 1000r²
1000r² + 2000r + 1000 <---- standard form.
Answer:
prime numbers are the natural numbers greater than one that are not products of two smaller natural numbers
Step-by-step explanation:
Answer:
$2,589.52
Step-by-step explanation:

We start with the compound interest formula above, where
A = future value
P = principal amount invested
r = annual rate of interest written as a decimal
n = number of times interest is compound per year
t = number of years
For this problem, we have
P = 2000
r = 0.026
n = 2
t = 10,
and we find A.


A convex polygon
Hope this helps :)
Answer:
all work is pictured and shown