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AnnyKZ [126]
3 years ago
7

The decimal equivalent of 5/3 is a repeating decimal​

Mathematics
1 answer:
Klio2033 [76]3 years ago
3 0

Answer:

1.6666666666666666

Step-by-step explanation:

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James used base-ten to show that 40 is one-tenth of 400. Explain your reasoning
Elanso [62]
Cause 400 divided by 10 is 40

3 0
3 years ago
Which choice is equivalent to the expression below ^-216​
Natali5045456 [20]

Answer:

B. 6i√6

General Formulas and Concepts:

<u>Algebra II</u>

  • Imaginary Numbers: √-1 = i

Step-by-step explanation:

<u>Step 1: Define expression</u>

√-216

<u>Step 2: Simplify</u>

  1. Factor:                     √-1 · √216
  2. Simplify:                   i · 6√6
  3. Multiply:                   6i√6
5 0
3 years ago
Read 2 more answers
In a home theater system, the probability that the video components need repair within 1 year is 0.02, the probability that the
earnstyle [38]

Answer:

(a) The probability that at least one of these components will need repair within 1 year is 0.0278.

(b) The probability that exactly one of these component will need repair within 1 year is 0.0277.

Step-by-step explanation:

Denote the events as follows:

<em>A</em> = video components need repair within 1 year

<em>B</em> = electronic components need repair within 1 year

<em>C</em> = audio components need repair within 1 year

The information provided is:

P (A) = 0.02

P (B) = 0.007

P (C) = 0.001

The events <em>A</em>, <em>B</em> and <em>C</em> are independent.

(a)

Compute the probability that at least one of these components will need repair within 1 year as follows:

P (At least 1 component needs repair)

= 1 - P (No component needs repair)

=1-P(A^{c}\cap B^{c}\cap C^{c})\\=1-[P(A^{c})\times P(B^{c})\times P(C^{c})]\\=1-[(1-0.02)\times (1-0.007)\times (1-0.001)]\\=1-0.97216686\\=0.02783314\\\approx 0.0278

Thus, the probability that at least one of these components will need repair within 1 year is 0.0278.

(b)

Compute the probability that exactly one of these component will need repair within 1 year as follows:

P (Exactly 1 component needs repair)

= P (A or B or C)

=P(A\cap B^{c}\cap C^{c})+P(A^{c}\cap B\cap C^{c})+P(A^{c}\cap B^{c}\cap C)\\=[0.02\times (1-0.007)\times (1-0.001)]+[(1-0.02)\times 0.007\times (1-0.001)]\\+[(1-0.02)\times (1-0.007)\times 0.001]\\=0.02766642\\\approx 0.0277

Thus, the probability that exactly one of these component will need repair within 1 year is 0.0277.

7 0
3 years ago
a farmhouse shelters 11 animals. Some are goats and some are ducks. Altogether there are 34 legs. How many of each animal are th
blagie [28]
There could be lots of answers. I'm going with 5 goats and 7 ducks.
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5/7+(-1/3)-(-1/2)<br><br> Show work pls
ELEN [110]
30/42-14/42+21/42= 37/42
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3 years ago
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