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3 years ago

Write the fractions13/60 and 11/20 as equivalent fractions with the least common denominator

Mathematics

1 answer:

goldenfox [79]3 years ago

4 0

Answer:13/60 33/60

Step-by-step explanation:

13/60 1/20

least common denominator for 60 and 20 is 60

13*1/60 3*11/60

13/60 33/60

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Find the value of x in each case. Give reasons to justify your solutions<br> Q ∈ PR

slavikrds [6]

The exterior angle theorem states that an exterior angle is equal to the sum of its remote interior angles.

With that we know...

m<QRS+m<RSQ=m<SQP

90+34=x+72

124=x+72

x=52 degrees

answer: 52 degrees

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3 years ago

Write 87.5% as a fraction in simplest form

Len [333]

87 1/2 is the answer. hope it help.

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3 years ago

D-t: 50. What is d an t to equal 50

Tanzania [10]

D-t=50
t=50
d-50=50
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3 years ago

Calculați aplicând distributivitatea înmulțirii fata de adunare și de scădere

solmaris [256]

Răspuns:

7/5;

2 întreg 5/12

Explicație pas cu pas:

6/7 × (2 numere întregi și 5 / 6-1 numere întregi și 1/5)

6/7 * (2 5/6 - 1 1/5)

6/7 * (17/6 - 6/5)

6/7 * (85 - 36) / 30

7/7 * 49/30

1/1 * 7/5

= 7/5

2.)

5/8 × 1 întreg și 2/3 + 11/5

5/8 * (1 2/3 + 11/5)

5/8 * (5/3 + 11/5)

5/8 * (25 + 33) / 15

5/8 * 58/15

1/8 * 58/3

= 58/24

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= 2 întreg 5/12

4 0

3 years ago

What are the ordered pairs of the

9966 [12]

Start by writing the system down, I will use $y$ to represent $f(x)$

$y=x^2-5x+3\wedge y=-3$

Substitute the fact that $y=-3$ into the first equation to get,

$-3=x^2-5x+3$

Simplify into a quadratic form ( $ax^2+bx+c=0$ ),

$x^2-5x+6=0$

Now you can use Vieta's rule which states that any quadratic equation can be written in the following form,

$x^2+x(m+n)+mn=0$

which then must factor into

$(x+m)(x+n)=0$

And the solutions will be $m,n$ .

Clearly for small coefficients like ours $5,6$ , this is very easy to figure out. To get 5 and 6 we simply say that $m=3, n=2$ .

This fits the definition as $5=3+2$ and $6=2\cdot3$ .

So as mentioned, solutions will equal to $m=3, n=2$ but these are just x-values in the solution pairs of a form $(x,y)$ .

To get y-values we must substitute 3 for x in the original equation and then also 2 for x in the original equation. Luckily we already know that substituting either of the two numbers yields a zero.

So the solution pairs are $(2,0)$ and $(3,0)$ .

Hope this helps :)

5 0

3 years ago