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Feliz [49]
3 years ago
8

Assume that Ray is 38 years old and has 27 years for saving until he retires. He expects an APR of​ 7.5% on his investments. How

much does he need to save if he puts money away annually in equal endminusofminustheminus year amounts to achieve a future value of​ $1,200,000 dollars in 27​ years' time
Business
1 answer:
blsea [12.9K]3 years ago
4 0

Answer:

$14,882.44.

Explanation:

Given

Future value= $1,200,00

Time= 27 years

Interest rate= 7.5%

let PV= present value

The question is solved by computing the amount of annual deposit.

Enter the below in a financial calculator to compute the amount of annual deposit:

FV= 1,200,000

N= 27

I/Y= 7.5

PV= FV÷(1+I)^N

putting values we get

PV= $1,185,117.56

Now Benefit = FV- PV= 1,200,000-1,185,117.85= $14,882.44.

Therefore, the amount of annual deposit is $14,882.44.

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Robin earns $44,000 per year and has current debt payments of $1,200 per month. she wants to buy a new car with desirable financ
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Recently, a certain bank offered a 5-year CD that earns 3.26% compounded continuously. Use the given information to answer the q
Maru [420]

Answer:

a. The CD will worth<u> $35,311 </u>in five years.

b. It will take <u>12.44 years </u>for the account to be worth $45,000.

Explanation:

a) If $30,000 is invested in this CD, how much will it be worth in 5 years?(Round to the nearest cent.)

This can be determined using the formula for calculating the future value (FV) compounding formula as follows:

FV = PV * e^(rn) ................................... (1)

FV = Future value in five years = ?

PV = Present value of amount invested = $30,000

e = Mathematical constant approximated as 2.7183

r = Interest rate = 3.26%, or 0.0326

n = number of years = 5

Substituting the values into equation (1), we have:

FV = $30,000 * 2.7183^(0.0326 * 5)

FV= $35,311

Therefore, the CD will worth<u> $35,311 </u>in five years.

(b) How long will it take for the account to be worth $45,000?(Round to two decimal places as needed)

Also, using equation (1) part a, we have:

FV = Future value in n years = $45,000

PV = Present value of amount invested = $30,000

e = Mathematical constant approximated as 2.7183

r = Interest rate = 3.26%, or 0.0326

n = number of years it will take to have $45,000 = ?

Substituting the values into equation (1), we have:

$45,000 = $30,000 * 2.7183^(0.0326 * n)

$45,000 / $30,000 = 2.7183^(0.0326 * n)

1.50 = 2.7183^(0.0326 * n)

Loglinearise both sides and solve for n, we have:

Log(1.50) = (0.0326 * n)Log(2.7183)

0.176091259055681 = 0.0326 * n * 0.434297385124509

0.176091259055681 = n * 0.014158094755059

n = 0.176091259055681 / 0.014158094755059

n = 12.44 years

Therefore, it will take <u>12.44 years </u>for the account to be worth $45,000.

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