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Alex787 [66]
3 years ago
7

What is the product of three square root of eight times four square root of three? Simplify your answer.

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
7 0
The\ product\ of 3 \sqrt{8}*4 \sqrt{3}\ is\ 24 \sqrt{6}.


First, recognize that all the numbers can be moved around because they are being multiplied together.
Next, rearrange the expression so that the whole-number coefficients are together:

3\sqrt{8}*4\sqrt{6}
3*4*\sqrt{8}*\sqrt{3}

Now try to simplify the square-roots to find any squares inside that can be reduced and taken out of the square-root:

3*4*\sqrt{(2*2*2)}*\sqrt{3}
3*4*\sqrt{4*2}*\sqrt{3}

Multiply the square roots together:
3*4*\sqrt{(4*2*3)}
3*4*\sqrt{(4*6)}

Now take out the square-root of 4 and simplify
3*4*\sqrt{4}*\sqrt{6}
3*4*(2)*\sqrt{6}
24\sqrt{6}

Thus,\ your\ answer\ is\ 24\sqrt{6}
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A small square pyramid of height 6 cm was removed from the top of a large square pyramid of height 12cm forming the solid shown.
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Answer:

15,872 mm³

Step-by-step explanation:

given:

A small square pyramid of height 6 cm was removed from the top of a large square pyramid of height 12cm forming the solid shown.

Find:

the exact volume of the solid

solution:

volume of square base pyramid = (base area)² * h/3

where total h = 12 cm

height of top pyramid (ht)= 6 cm

height of bottom pyramid (hb) = 6 cm

bottom volume =  total volume - the volume on top

so,

total volume = 1/3 (base area)² h

                     = 1/3 (8*8)² * 12

                     = 16,384 mm³

volume on top = 1/3 (top base area)² h

                         = 1/3 (4*4)² * 6

                         = 512 mm³

finally: get the bottom volume:

bottom volume =  total volume - the volume on top

bot. vol = 16,384 mm³ - 512 mm³

             = 15,872 mm³

therefore,

the volume of the cut  pyramid base = 15,872 mm³

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Step-by-step explanation:

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Step-by-step explanation:

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The answer is 32
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